How to calculate fractions smallest to largest?
1 answer:
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Answer:
The average inventory depends on the manufacturing batch size.
Its formula is:
Step-by-step explanation:
The question is incomplete.
Question complete:
<em>"A machine makes two components, call them type A and B. It takes 250 seconds to switch production between the component types. During that time no production occurs. When in production, each unit of A or B requires 0.5 seconds to be completed. The two components, A and B are combined in an assembly process to make a final product, call it C. The assembly step can combine the two components into 1 unit every 2 seconds. What is the average inventory of B components?"</em>
We have two steps in this process: the manufacturing of A and B and the assembly process.
We are not told about the batch size, so we will treat that as a variable called n. This represents the amount of units (of A or B) that are manufactured per cycle.
Time (seconds) to manufacture n units of A and n units of B:
Time (seconds)to assemble n units of C
Then the total time of the cycle is:
The average inventory of B is n units per cycle, which lasts (3n+250) seconds.
For a batch size of 100 units, the average inventory is:
For a batch size of 1,000 units, the average inventory is:
Let length = l
width = w
length = 3 times width = 3w
Area of the land = 75 sq. m
Area = length × width = 3w×w = 75
3w²=75
w²=25
w=5 m
length = 3×15 = 15m
Now lets make the figure with the path of width x meters
(Refer the attached figure for easy understanding)
The inner length is the length of the rectangle reduced by x meters on either side due to the path
that is 15-x-x = 15-2x
the inner width is the width reduced by x meters in either side
= 5-x-x = 5-2x
Now lets calculate the inner area = inner length × inner width
(15-2x)×(5-2x)
=
= sq. m
Now the function to calculate the cost
f(x) is given by $3.00 × area of the inner land
f(x) = 3 × {75-40x+4x²)
= 225-120x+12x²
or
= 12x²-120x+225
