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spayn [35]
2 years ago
8

Give me lil reasoning so I know your not lying for points

Chemistry
1 answer:
jeka942 years ago
3 0

Answer:

0.01 psi

Explanation:

If you look at the data points plotted on the graph, the slope of the line touches 0.1 for the y-axis when it is at 20 for the x-axis.

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Some rice farmers burn their fields after harvest to remove leftover plant material and kill certain plant pests. You are resear
WARRIOR [948]
I think its proably 3.....
5 0
3 years ago
If a chemical has a pH of 3, how could you alter its pH value to be more basic?
Andreyy89

Answer; If a chemical has a pH of 3, how could you change its pH value to be more basic? Adding water to a chemical will dilute the acid, thus lowering the pH value to more basic.

6 0
3 years ago
Why was there so much disagreements among the ancient greeks about the nature of the atoms?
olga2289 [7]
It is because in that time science was not established. This is, the experimentation to test hypotheses, which is a fundamental part of the scientific method, was not applied.

Atoms can not be seen, then they could only reflect or philosophize on this matter. This method is not able to give good answers to so complicated scientific matters.

 
4 0
3 years ago
An amphoteric salt is one that contains an anion that can act as either an acid or a base in water. Baking soda, NaHCO3, is an e
LenKa [72]

Answer:

pH = 8.34

Explanation:

The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:

H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>

<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>

Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:

pKa1 = 6.37; pKa2 = 10.32

As the pH of amphoteric salts is:

pH = (pKa1 + pKa2) / 2

<h2>pH = 8.34</h2>
3 0
2 years ago
A 2.26 M solution of KOH is prepared. Calculate the moles and mass of solute present in a 15.2-mL sample of this solution. The m
kenny6666 [7]

Answer:

0.0344 moles and 1.93g.

Explanation:

Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:

<em>Moles KOH:</em>

15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles

<em>Mass KOH:</em>

0.0344 moles * (56.11g/mol) = 1.93g of KOH

7 0
3 years ago
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