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4 years ago

An airplane crash a woman is holding a

Chemistry

1 answer:

Tom [10]4 years ago

3 0

What does the rest of the statement say

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Why do we use acid during the detection of halogens

ohaa [14]

Answer:

Nitric acid decomposes sodium cyanide and sodium halide. else, they precipitate in test and misguide the result. Therefore, dilute nitric acid is added before testing halogens to expel all the gases if evolved.

8 0

2 years ago

La precipitación ácida es un agente de?

katrin2010 [14]

Answer:

Explanation:

por que si

6 0

3 years ago

Read 2 more answers

Why blowing at the ping ping ball did not change its shape and size?

goldfiish [28.3K]

Answer:

Because it does not have to

Explanation:

Why because when you blow at it it might move it does not change it's shape because it is a solid

4 0

2 years ago

What is the lewis structure for CH2ClCOO-

FrozenT [24]

Answer: The Lewis structure of Chloroacetate can be found at the attachment below.

Explanation:

CH2ClCOO- The chemical compound is called Chloroacetate.

Reference link for the Chloroacetate structure.

https://www.google.com/search?q=lewis+structure+for+CH2ClCOO-&prmd=ivn&sxsrf=ALeKk03mQcLiY-q5pEriMR0_26ZTXLjmJg:1589680325594&source=lnms&tbm=isch&sa=X&ved=2ahUKEwjfxPPY5LnpAhVloXEKHeAwD-wQ_AUoAXoECA4QAQ&cshid=1589680746615&biw=360&bih=559&dpr=3#

5 0

3 years ago

The normal boiling point of ethanol (C2H5OH) is 78.3 oC and its molar enthalpy of vaporization is 38.56 kJ/mol. What is the chan

Sloan [31]

Answer:

The change in entropy in the system is -231.5 J/K

Explanation:

Step 1: Data given

The normal boiling point of ethanol (C2H5OH) is 78.3 °C = 351.45 K

The molar enthalpy of vaporization of ethanol is 38.56 kJ/mol = 38560 J/mol

Mass of ethanol = 97.2 grams

Pressure = 1 atm

Step 2: Calculate the entropy change of vaporization

The entropy change of vaporization = molar enthalpy of vaporization of ethanol / temperature

The entropy change of vaporization = 38560 J/mol / 351.45 K

The entropy change of vaporization = -109.72 J/k*mol

Step 3: Calculate moles of ethanol

Moles ethanol = mass / molar mass ethanol

Moles ethanol = 97.2 grams / 46.07 g/mol

Moles ethanol = 2.11 moles

Step 4: Calculate change in entropy

For 1 mol = -109.72 J/K*mol

For 2.11 moles = -231.5 J/K

The change in entropy in the system is -231.5 J/K

7 0

3 years ago