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8_murik_8 [283]
3 years ago
14

Many bacteria cannot reproduce and cooler temperatures in our destroyed at high temperatures. How do you humans take advantage o

f this fact when preparing and storing food?
Chemistry
1 answer:
12345 [234]3 years ago
3 0

freezer and refrigerator too cold for most bacteria to grow .oven too hot for bacteria to survive

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Write the net chemical equation for the production of nitric acid from nitrogen, hydrogen and oxygen. be sure your equation is b
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<span>Nitric acid is often manufactured from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming of natural gas, in a two-step process. In the first step, nitrogen and hydrogen react to form ammonia: In the second step, ammonia and oxygen react to form nitric acid and water:</span>
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What is the connection between Oobleck and the mantle?
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Explanation:

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2 years ago
If you determine the molar heat of neutralization for an acid is 49.1 kJ/mol and the accepted value is found to be 55.2 kJ/mol,
zhenek [66]

Answer: % Errror = 11.05%

Explanation:

Percentage error is the difference between the measured value and the theoretical value as expressed in percent.

That is;

% Error =

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Theoretical value =55.2kJ

Measured value = 49.1kJ

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%Error = 6.1/55.2 ×100

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5 0
3 years ago
SCIENCE HELP! 10 POINTS
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A relatively simple way of estimating profit is to consider the the difference between the cost (the total spent on materials an
Maksim231197 [3]
<span>Answer: it shows that 1mol mCPHA provides the oxygens to 1 mol of propene, to make 1 mole of C3H6O so: 1 mol C3H6 & 1 mol mCPHA --> 1 mol C3H6O using molar masses, that equation becomes: 42.08grams C3H6 & 172.57grams mCPHA --> 58.08grams C3H6O which is: 42.08 kg C3H6 & 172.57 kg mCPHA --> 58.08 kg C3H6O to produce 1 kg of C3H6O, this becomes: 42.08 / 58.08 kg C3H6 & 172.57 / 58.08 kg mCPHA --> 58.08 /58.08 kg C3H6O which is: 0.72452 kg C3H6 & 2.9712 kg mCPHA --> 1 kg C3H6O but because the reaction gives only a 96% yield, we scale up the reactants to get that desired 1 kg of C3H6O (0.72452 kg ) (100/96) C3H6 & (2.9712 kg) (100/96) mCPHA --> 1 kg C3H6O which is: 0.75471 kg C3H6 & 3.095 kg mCPHA --> 1 kg C3H6O ========= costs per kg of C3H6O produced: (0.75471 kg C3H6) ($10.97 per kg) = $8.279 (3.095 kg mCPHA) ($5.28 per kg) = $16.342 & (0.75471 kg C3H6) / (0.0210 kg C3H6 / L dichloromethane) = 35.939 Litres dichloromethane (35.939 Litres dichloromethane) ($2.12 per L) = $ 76.19 & waste disposal is $5.00 per kilogram of propene oxide produced total cost, disregarding labor,energy, & facility costs: $8.279 & $16.342 & $ $ 76.19 & $5.00 = $105.81 per kg C3H6O produced ========== profit: ($258.25 / kg C3H6O) - ($105.81 cost per kg) = $152.44 profit /kg “Calculate the profit from producing 75.00kg of propene oxide” (75.00kg) ($152.44 /kg) = $11,433 that answer rounded off to four sig figs, is $11,430</span>
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3 years ago
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