The earth is not a star . why?

A ball is thrown upward at a 45∘∘ angle. In the absence of air resistance, the ball follows a_________. A. A ball is thrown upwa

enot [183]

Answer:

C. parabolic Curve

Explanation:

The trajectory of a projectile motion is parabolic.

If a ball is thrown at angle of 45° to the horizontal then it will follow a parabolic curve during its motion as its a projectile motion. The other options are incorrect as sine curve is a periodic type of curve. linear curve and tangential curve are also out of place.So option C is correct

8 0

3 years ago

A force of 10 newtons acts in a direction 75° above horizontal, moving an object 15 meters from (0, 0) to (15, 0). what is the w

hammer [34]

Work done by the force is 150 Joules.

Steps involved in the question:

Step one:

Given data

Force F= 10N

the distance is described by the coordinate = (0,0) to (15,0)

hence the distance = 15m in the x-direction.

Step two:

Required is the work done

we know that work done is expressed as

Wd= Force* Distance

Wd= 10*15

Wd= 150 Joules

To learn more about work done refer : brainly.com/question/25573309

#SPJ4

6 0

2 years ago

A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.

strojnjashka [21]

Answer:

$D=99.4665307m \approx 99.5m$

Explanation:

From the question we are told that

Mass $m=6kg$

Velocity of mass $V_m=16$

Force of Tunnel $F_t=8N$

Length of Tunnel $L_t=1.6$

Height of frictional incline $H_i=2.9$

Angle of inclination $\angle =16 \textdegree$

Acceleration due to gravity $g=9.8m/s^2$

First Frictional surface has a coeﬃcient $\alpha_1 =0.21\ for\ d_c=1$

Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

Generally the initial Kinetic energy is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}(6)(16)^2$

$K.E=768$

Generally the work done by the Tunnel is mathematically given as

$w_t=F_t*d_t$

$w_t=8*1.6$

$w_t=12.8J$

Therefore

$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

$E_t=K.E+E_t\\E_t=768J+12.8J$

$E_t=780.8J$

Generally the energy lost while climbing is mathematically given as

$E_c=mgh$

$E_c=(6)(9.8)(2.9)$

$E_c=170.52J$

Generally the energy lost to friction is mathematically given as

$E_f=\alpha *m*g*cos\textdegree*d_c$

$E_f=0.21*6*9.8*cos16*1$

$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

$E_m=585.48J$

Since

$E_m=\alpha_2*g*m*d$

Therefore

It slide along the second frictional region

$D=\frac{585.46}{0.1*9.81*6}$

$D=99.4665307m \approx 99.5m$

6 0

3 years ago

1 point

madreJ [45]

Answer:

just multiply the frequency and wavelength

200× 2

400

3 0

3 years ago

For small angles, does the pendulum's period of oscillation depend on initial angular displacement from equilibrium? Explain.

aksik [14]

Answer:

No, the pendulum's period of oscillation does not depend on initial angular displacement.

Explanation:

Given that,

For small angle, the pendulum's period of oscillation depend on initial angular displacement from equilibrium.

We know that,

The time period of pendulum is defined as

$T=2\pi\sqrt{\dfrac{l}{g}}$

Where, l = length of pendulum

g = acceleration due to gravity

So, The time period of pendulum depends on the length of pendulum and acceleration due to gravity.

It does not depend on the initial angular displacement.

Hence, No, the pendulum's period of oscillation does not depend on initial angular displacement.

6 0

3 years ago

The earth is not a star . why?​

The earth is not a star . why?