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bixtya [17]
3 years ago
12

How do we determine the conditions that existed in the very early universe? A We can only guess at the conditions, since we have

no way to calculate or observe what they were. B The conditions in the very early universe must have been much like those found in stars today, so we learn about them by studying stars. C From the current expansion rate we can work backward to estimate temperature and densities at various times in the early universe. D By looking all the way to the cosmological horizon, we can see the actual conditions that prevailed all the way back to the first instant of the Big Bang.
Physics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

D By looking all the way to the cosmological horizon, we can see the actual conditions that prevailed all the way back to the first instant of the Big Bang.

Explanation:

Astrophysicists are able to determine the conditions that existed in the early universe, by using instruments such as telescopes to observe and study cosmic horizons. More ideas about the early universe can be found from the thermal light present in cosmic backgrounds.

Scientists study these details that provide an insight into the conditions that existed so many years ago. They have been able to determine that the Big Bang involved so many collisions from these observations.

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A satellite orbits the moon for 3685 s. It has an orbital radius of 2008177 m. What is the acceleration of the satellite?
Anna11 [10]

A satellite orbits the moon for 3685 s. It has an orbital radius of 2008177 m. then the acceleration of the satellite would be 5.832 m/s²

<h3 /><h3>What is a uniform circular motion?</h3>

It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction but the speed of the object is constant in a uniform circular motion

The acceleration during the uniform circular motion is given by the formula

a = v²/r

where a is the acceleration

v is the velocity of the object

r is the radius of the orbit

As given in the problem a satellite orbits the moon for 3685 s. It has an orbital radius of 2008177 m.

velocity of the satellite

v = 2πr/t

v= (2×3.14×2008177)/3685

v = 3422.34 m/s

acceleration of the satellite

a = v²/r

a =  3422.34²/2008177

a = 5.832 m/s²

Thus, the acceleration of the satellite would be 5.832 m/s²

Learn more about uniform circular motion from here

brainly.com/question/2285236

#SPJ1

7 0
2 years ago
Explain how the force of air resistance depends on an object's speed
nalin [4]
There must be a equal opposite reaction. E=mv2
8 0
4 years ago
A car's position in relation to time is plotted on the graph. What is the car's average velocity for segment C? A) -4 m/s B) -0.
kotegsom [21]

Answer:

b

Explanation:

its the anwser

7 0
3 years ago
What is kepler's law??​
Elan Coil [88]
<h2>QUESTION:- </h2>

➜what is kepler's law??

\huge\red{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W}\orange{ER}}}}

Kepler gave the three laws or theorems of motion of the orbitals bodies

{\huge {\bold{ \red{ \star}}}}{ \blue{ \bold{FIRST \: \: \: LAW}}}

This law state that the celestial bodies revolves around the stars in elliptical orbit and star as a single focus.

Example :- Earth revolves around the Sun as assuming it as single focus

This also shows that earth revolves around the sun in elliptical orbit.

{\huge {\bold{ \blue{ \star}}}}{ \green{ \bold{SECOND \: \: \: LAW}}}

Area covered by the planet is equal in equal duration of time irrespective of the position of the planet.

It also states that Angular momentum is constant

As Angular momentum is constant it means areal velocity is also constant.

\frac{ \triangle \: A}{ \triangle \: T} = \frac{L}{2m}△T△A=2mL

where:-

A is the area.

T is the time.

L is the angular momentum.

M is the mass of the body.

{\huge {\bold{ \green{ \star}}}}{ \purple{ \bold{THIRD \: \: \: LAW}}}

square of the time of the revolution is directly proportional to the cube of the distance between the planet and star in Astronomical unit.

{T}^{2} = {a}^{3}T2=a3

where:-

T = time of revolution

a is the distance between the planet and star.

\purple\star \: {Thanks \: And \: Brainlist} \blue \star \\ {\orange{ \star}}{if \: U \: Like d \: My \: Ans} {\green{ \star }}

8 0
3 years ago
Locate the polyatomic ion in the compound CaCO3 <br> Ca <br> 0 <br> CO3 <br> C
dimaraw [331]

CO₃

Explanation:

The polyatomic ion in the compound CaCO₃ is CO₃.

A polyatomic ion is an ion that is made up of more than one atom that has singular property.

They are usually called radicals.

    CaCO₃ ⇒  Ca²⁺  + CO₃²⁻

CO₃²⁻ is a polyatomic ion because it is made up of more than one atom.

The CO₃²⁻ is called a carbonate group.

It is made up of:

  • one atom of carbon
  • 3 atoms of oxygen
  • a net charge of 2-

learn more:

Polyatomic ions brainly.com/question/6786947

#learnwithBrainly

4 0
3 years ago
Read 2 more answers
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