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Vilka [71]
3 years ago
7

: A personal computer manufacturer buys 36% of its chips from Japan and the rest from the United St...

Mathematics
1 answer:
meriva3 years ago
3 0

Answer: 0.9862

Step-by-step explanation:

Given : The probability that the chips belongs to Japan: P(J)= 0.36

The probability that the chips belongs to United States : P(U)= 1-0.36=0.64

The proportion of Japanese chips are defective : P(D|J)=0.017

The proportion of American chips are defective : P(D|U)=0.012

Using law of total probability , we have

P(D)=P(D|J)\times P(J)+P(D|U)\times P(U)\\\\\Rightarrow\ P(D)=0.017\times0.36+0.012\times0.64=0.0138

Thus , the probability that chip is defective = 0.0138

Then , the probability that a chip is defect-free=1-0.0138=0.9862

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