Answer: 0.9862
Step-by-step explanation:
Given : The probability that the chips belongs to Japan: P(J)= 0.36
The probability that the chips belongs to United States : P(U)= 1-0.36=0.64
The proportion of Japanese chips are defective : P(D|J)=0.017
The proportion of American chips are defective : P(D|U)=0.012
Using law of total probability , we have
![P(D)=P(D|J)\times P(J)+P(D|U)\times P(U)\\\\\Rightarrow\ P(D)=0.017\times0.36+0.012\times0.64=0.0138](https://tex.z-dn.net/?f=P%28D%29%3DP%28D%7CJ%29%5Ctimes%20P%28J%29%2BP%28D%7CU%29%5Ctimes%20P%28U%29%5C%5C%5C%5C%5CRightarrow%5C%20P%28D%29%3D0.017%5Ctimes0.36%2B0.012%5Ctimes0.64%3D0.0138)
Thus , the probability that chip is defective = 0.0138
Then , the probability that a chip is defect-free=![1-0.0138=0.9862](https://tex.z-dn.net/?f=1-0.0138%3D0.9862)