Answer: $13.95
50%+ of 9.30 is 13.95 (if you do the math)
Add them all.34,6000 and 15000 and 2900 and 4050
2,800
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Answer:
(A) AA Similarity Theorem
Step-by-step explanation:
Given: AB ∥ DE
To Prove: 
Given Triangle ABC with Line DE drawn inside of the triangle and parallel to side AB. The line DE forms a new triangle DCE.
Because AB∥DE and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines.
Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
We can state ∠C ≅ ∠C using the reflexive property.
Therefore,
by the AA similarity theorem.
Remark: In the diagram, we can see that the two triangles share Angle C and have two equal angles at E and B. Therefore, they are similar by the Angle-Angle Similarity Theorem.
In figure,
AC = BC (given)
Since, in a triangle , angles opposite to equal sides are also equal.
Therefore,
b= 52°
Now,
°.° c is exterior angle of triangle.
.°. c = b + 52°
=> c = 52° + 52°
=> c = 104°
Solution:-
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b = 52° & c =104°
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