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joja [24]
3 years ago
14

What does the statement “10m/s to the north” describe

Physics
1 answer:
Lilit [14]3 years ago
7 0

Since it tells both a speed and a direction, it describes a motion vector called "velocity".

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According to newton's second law, if you have an object that is put under acceleration due to a force, how could you reduce the
expeople1 [14]

Answer:

We could reduce the force or increase the mass of the object.

Explanation:

Using the definition of force, according to Newton's second law,  (F = ma) the acceleration is directly proportional to the force and inversely proportional to the mass. Therefore, if we want to reduce the acceleration of an object we have two options:

  1. We could reduce the force
  2. We could increase the mass

In both cases a will decrease.  

I hope it helps you!

7 0
3 years ago
How does temperature affect Brownian motion
Elan Coil [88]

Answer:

Explanation:

Temperature is the measure of average kinetic energy or energy in motion in a molecules. Brownian motion measure kinetic energy or how energetic the motion is and it is proportional to temperature.

Therefore, an increase in Temperature will bring about increase in kinetic energy of brownian motion. It will speed it up.

3 0
3 years ago
The volume of a gas can be converted to moles by
BaLLatris [955]
B. Because I say so
6 0
3 years ago
Which example best demonstrates how unbalanced forces change the speed of an object's motion?
exis [7]

I don’t see a picture but unbalanced forces could be two boys pushing with a combined force of 400 Newton’s but the surface of what the box is laying on being 600 meaning since the ground is creating a higher force in the form of friction it will slow the boys down. When forces are unbalanced it means that the object can not be still or moving at a constant speed  when one force is greater by a significant amount the object either slows quickly or accelerates fast depending on which factor is greater.

4 0
3 years ago
Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assu
Elenna [48]

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424  x 10²⁵

= 6.4 x 10²³ kg .

4 0
3 years ago
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