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Lesechka [4]
3 years ago
12

Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assu

me that Phobos's orbit is circular. Calculate the mass of Mars. Express your answer in units of kg. (Hint: Use the circular orbit velocity formula ; remember to use units of meters, kilograms, and seconds.) Please round the answer to four significant digits. m
Physics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424  x 10²⁵

= 6.4 x 10²³ kg .

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To solve the exercise it is necessary to use the reciprocal Lorenz factor of the special theory of relativity with the pulse rate.

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PART A) For the given values we can replace it at the previous equation,

\Xi = Pulse_{astronaut} *\sqrt{1-\frac{v^2}{c^2}}

\Xi = 66beats/min * \sqrt{1-\frac{(0.49c)^2}{c^2}}

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\Xi = 66beats/min * \sqrt{1-\frac{(0.94c)^2}{c^2}}

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8 0
3 years ago
Which of the following is an instantaneous speed?
Brilliant_brown [7]

Answer:

A: All of the above

Explanation:

The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.

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5 0
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hope this helps
6 0
4 years ago
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vesna_86 [32]

Answer:

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