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3 years ago

The interval shown here represents a

Physics

1 answer:

k0ka [10]3 years ago

6 0

Answer:strong base

Explanation:

1 is strong, 14 is weak. And it is a ph scale so it wouldn't be a base. It would be a acid

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If the voltage in the circuit was 6.0 V with current of 2.0 A. What is the resistance?

rewona [7]

Answer:

3 Ω

Explanation:

Recall that Voltage = Current x Resistance

We are given that voltage = 6.0V and Current is 2.0 A.

Substituting these into the equation:

Voltage = Current x Resistance

6.0 = 2.0 x Resistance

Resistance = 6.0 / 2.0 = 3 Ω

6 0

4 years ago

Read 2 more answers

Charge q1 is distance s from the negative plate of a parallel-plate capacitor. Charge q2=q1/3 is distance 2s from the negative p

Svetlanka [38]

Answer:

The ratio (U₁/U₂) = 6

Explanation:

U, the potential energy is given as

U = kqQ/r

k = Coulomb's constant

q = charge we're concerned about

Q = charge of the negative plate of the capacitor

r = distance of q from the negative plate of the capacitor.

For charge q₁

U₁ = kq₁Q/s

U₂ = kq₂Q/2s

But q₂ = q₁/3

U₂ becomes U₂ = kq₁Q/6s

U₁ = kq₁Q/s

U₂ = kq₁Q/6s

(U₁/U₂) = 6

5 0

4 years ago

What is a disadvantage of using nuclear power to produce electricity?

lianna [129]

Answer:

Explanation:

6 0

3 years ago

samantha a high school teacher wants to spend more time with her children and is looking for a job in her field. what would be a

sp2606 [1]

She could look for an online job or a job she can work at from home.

3 0

3 years ago

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A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k

Bad White [126]

Answer:

$v_{f,w} = 1.791\,\frac{m}{s}$ , $v_{f,c} = 0.972\,\frac{m}{s}$

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

$I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}$

The final angular speed is:

$\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}$

$\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev} \right)$

$\omega_{f} \approx 5.116\,\frac{rad}{s}$

The tangential velocities of the wheel and the clay are, respectively:

$v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )$

$v_{f,w} = 1.791\,\frac{m}{s}$

$v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )$

$v_{f,c} = 0.972\,\frac{m}{s}$

5 0

3 years ago