1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arturiano [62]
3 years ago
12

The interval shown here represents a

Physics
1 answer:
k0ka [10]3 years ago
6 0

Answer:strong base

Explanation:

1 is strong, 14 is weak. And it is a ph scale so it wouldn't be a base. It would be a acid

You might be interested in
The stored energy an object has due to its MOTION system transformation
jekas [21]

Answer:A

Explanation:

Kinetic energy is energy caused by motion.a body in motion possess kinetic energy

3 0
4 years ago
Một loa phát ra với cường độ âm là 40 (W/m2<br><br> ). Mức cường độ âm của loa thuộc phạm vi?
motikmotik

Answer:ew

Explanation:

qeeqw

8 0
3 years ago
A piece of charcoal used for cooking is found at the remains of an ancient campsite. A 1.09 kg sample of carbon from the wood ha
fgiga [73]

Answer:

t = 17199 years

Explanation:

given,

mass of sample = 1.09 Kg

Activity of living material   = 15 decays / min /g

Activity of living material   = 15 x 1000 decays /min /kg

Activity of living material per 1.09 kg A = 1.09 x 15 x 1000 decays / min

Activity of after time t is A ' = 2020

half life = 57300 years

desegregation constant

λ = 0.693 / 5700

A'= A e^{-\lambda\ t}

A'= 1.09 \times 15 \times 1000 e^{-\lambda\ t}

2020= 1.09 \times 15 \times 1000 e^{-\dfrac{0.693}{5700}\times t}

0.124=e^{-\dfrac{0.693}{5700}\times t}

taking ln both side

\dfrac{0.693}{5700}\times t = 2.09

t = 17199 years

5 0
3 years ago
While visiting the planet Mars, Moe leaps straight up off the surface of the Martian ground with an initial velocity of 105 m/s
yawa3891 [41]

Answer:

L = 0 m

Therefore, the cricket was 0m off the ground when it became Moe’s lunch.

Explanation:

Let L represent Moe's height during the leap.

Moe's velocity v at any point in time during the leap is;

v = dL/dt = u - gt .......1

Where;

u = it's initial speed

g = acceleration due to gravity on Mars

t = time

The determine how far the cricket was off the ground when it became Moe’s lunch.

We need to integrate equation 1 with respect to t

L = ∫dL/dt = ∫( u - gt)

L = ut - 0.5gt^2 + L₀

Where;

L₀ = Moe's initial height = 0

u = 105m/s

t = 56 s

g = 3.75 m/s^2

Substituting the values, we have;

L = (105×56) -(0.5×3.75×56^2) + 0

L = 0 m

Therefore, the cricket was 0m off the ground when it became Moe’s lunch.

5 0
3 years ago
Kinematics in 1D [4B.R]:Question 3
Stels [109]

Answer:

Only if the acceleration is uniform

6 0
4 years ago
Other questions:
  • How would you find the total energy stored in the
    15·1 answer
  • Calculate the power a car engine contributes to speeding the 1400 kg car up to a highway speed of 60.0 mi/h in 14.0 s.
    10·2 answers
  • A water tower has a pressure of 411340 Pa at the bottom. The density of water is 1000 kg/m^3. Find the depth of the water in m.
    9·1 answer
  • The model of the atom that described electrons scattered throughout a ball of positive charge was proposed by
    5·1 answer
  • A softball is thrown from the origin of an x-y coordinate system with an initial speed of 18 m/s at an angle of 35∘ above the ho
    12·1 answer
  • Do these examples represent unbalanced or balanced forces?
    11·1 answer
  • The moon completes one (circular) orbit of the earth in 27.3 days. The distance from the earth to the moon is 3.84×108 m. What i
    12·1 answer
  • Can anyone help me to explain theory of relativity??? ​
    13·1 answer
  • What is the peacocks displacement from 2 to 3 seconds
    11·1 answer
  • PART 3: The KINEMATIC EQUATION PROBLEMS/CALCULATIONS
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!