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3 years ago

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A piece of charcoal used for cooking is found at the remains of an ancient campsite. A 1.09 kg sample of carbon from the wood ha

s an activity of 2020 decays per minute. Find the age of the charcoal. Living material has an activity of 15 decays/minute per gram of carbon present and the half-life of 14C is 5730 y. Answer in units of y.

1 answer:

fgiga [73]3 years ago

5 0

Answer:

t = 17199 years

Explanation:

given,

mass of sample = 1.09 Kg

Activity of living material = 15 decays / min /g

Activity of living material = 15 x 1000 decays /min /kg

Activity of living material per 1.09 kg A = 1.09 x 15 x 1000 decays / min

Activity of after time t is A ' = 2020

half life = 57300 years

desegregation constant

λ = 0.693 / 5700

$A'= A e^{-\lambda\ t}$

$A'= 1.09 \times 15 \times 1000 e^{-\lambda\ t}$

$2020= 1.09 \times 15 \times 1000 e^{-\dfrac{0.693}{5700}\times t}$

$0.124=e^{-\dfrac{0.693}{5700}\times t}$

taking ln both side

$\dfrac{0.693}{5700}\times t = 2.09$

t = 17199 years

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