Answer:
15.21 %
Explanation:
If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:
p + q = 1
p² + 2pq + q² = 1
where;
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Given that p= 0.68 and q = 0.39
the percentage of the homozygous recessive genotype (q² ) will be
(0.39)² = 0.1521
= 0.1521 × 100
= 15.21 %
∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
Yes because the human body is comprised of several different systems that must work together to carry out the various processes necessary for good health.
Answer:
stem cells
Explanation:
Stem cells differ from other kinds of cells in the body. All stem cells—regardless of their source—have three general properties: they are capable of dividing and renewing themselves for long periods; they are unspecialized; and they can give rise to specialized cell types.
Answer:
Rough ER - modifying lipids
Explanation:
Rough ER does not modify lipids! Smooth ER does that! Hope this helps :)
The answer is an aminoacyl-tRNA synthetase.
<span> The aminoacyl-tRNA synthetase is an enzyme responsible for the attachment of an amino acid to tRNA. First, it binds the ATP and the amino acid which results in aminoacyl-AMP and inorganic pyrophosphate. Aminoacyl-AMP binds the appropriate tRNA molecule. The aminoacyl group dissociates from the complex with AMP and binds the tRNA molecule creating aminoacyl-tRNA.</span>
