Explanation:
Given that,
Number of turns in the coil, N = 100
Area of the coil, A = 100 cm² = 0.01 m²
It is placed at an angle of 70°.
Magnetic field, B = 0.1 Wb/m²
We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.
Magnetic flux is given by :
![\phi =BA\cos\theta\\\\\text{For N turns},\\\phi =NBA\cos\theta \\\\\phi=100\times 0.1\times 0.01\times \cos(70)\\\\=0.034\ Wb](https://tex.z-dn.net/?f=%5Cphi%20%3DBA%5Ccos%5Ctheta%5C%5C%5C%5C%5Ctext%7BFor%20N%20turns%7D%2C%5C%5C%5Cphi%20%3DNBA%5Ccos%5Ctheta%20%5C%5C%5C%5C%5Cphi%3D100%5Ctimes%200.1%5Ctimes%200.01%5Ctimes%20%5Ccos%2870%29%5C%5C%5C%5C%3D0.034%5C%20Wb)
So, the magnetic flux through the coil is 0.1 Wb.
Emf induced in the coil is :
![\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{0.034}{10^{-3}}\\\\=34\ V](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7B-d%5Cphi%7D%7Bdt%7D%5C%5C%5C%5C%3D%5Cdfrac%7B0.034%7D%7B10%5E%7B-3%7D%7D%5C%5C%5C%5C%3D34%5C%20V)
So, 34V of emf is induced in the coil.
Catalysts are used in the oil industry to increase octane
ratings in gasoline. Octane ratings tell how much fuel has to be compressed to
promote better fuel ignition in some
cars. The catalytic effect that
would be most beneficial for the oil industry is that more products can be
formed from a given amount of material.
Answer:
Slit separation, ![d=1.13\times 10^{-5}\ m](https://tex.z-dn.net/?f=d%3D1.13%5Ctimes%2010%5E%7B-5%7D%5C%20m)
Explanation:
It is given that,
Wavelength of light, ![\lambda=645\ nm=645\times 10^{-9}\ m](https://tex.z-dn.net/?f=%5Clambda%3D645%5C%20nm%3D645%5Ctimes%2010%5E%7B-9%7D%5C%20m)
The angle between the central bright fringe and the second dark fringe, ![\theta=4.9^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D4.9%5E%7B%5Ccirc%7D)
In case of double slits, the condition for dark fringe is given by :
![d\ sin\theta=(n-\dfrac{1}{2})\lambda](https://tex.z-dn.net/?f=d%5C%20sin%5Ctheta%3D%28n-%5Cdfrac%7B1%7D%7B2%7D%29%5Clambda)
n = 2
![d\ sin\theta=\dfrac{3}{2}\lambda](https://tex.z-dn.net/?f=d%5C%20sin%5Ctheta%3D%5Cdfrac%7B3%7D%7B2%7D%5Clambda)
![d=\dfrac{3\lambda}{2\ sin\theta}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B3%5Clambda%7D%7B2%5C%20sin%5Ctheta%7D)
![d=\dfrac{3\times 645\times 10^{-9}}{2\ sin(4.9)}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B3%5Ctimes%20645%5Ctimes%2010%5E%7B-9%7D%7D%7B2%5C%20sin%284.9%29%7D)
![d=1.13\times 10^{-5}\ m](https://tex.z-dn.net/?f=d%3D1.13%5Ctimes%2010%5E%7B-5%7D%5C%20m)
So, the slit separation is
. Hence, this is the required solution.
The Noble Gases are the most unreactive b/c its outermost shell completes the energy level and is stable enough.
Elements in the each group have the same number of valence electrons.
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