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2 years ago

If a body has a velocity 50 m s-1

Physics

1 answer:

lina2011 [118]2 years ago

6 0

Answer:

Using the relation V^2 = U^2 + 2× a× S

V^2 = 50^2 + (2× 5 × 240 )

V^ 2 = 2500 + 2400

V^ 2 = 4900

V= (4900)^0.5 = 70 m/s

hence, velocity at a distance of 240 m will be 70m/s.

Now using the relation,

V= U + a× t

70 = 50 + 5 × t

20 = 5 × t

t = 20/5 = 4m/s

hence , time required to travel a distance of 240m will be 4s.

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3 years ago

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2 years ago

Consider a container of oxygen gas at a temperature of 23°C that is 1.00 m tall. Compare the gravitational potential energy of a

Sergio039 [100]

Answer:

Yes, it is reasonable to neglect it.

Explanation:

Hello,

In this case, a single molecule of oxygen weights 32 g (diatomic oxygen) thus, the mass of kilograms is (consider Avogadro's number):

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4 years ago

A particle is moving along a projectile path where the initial height is 160 feet with an initial speed of 144 feet per second.

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s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. 

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Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet.

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4 years ago

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