Question

3. A cat pushes a 0.25-kg toy with a net force of 8 N. According to Newton's second

Answer 1

• Mass=0.25kg
• Force=8N

$\\ \sf{:}\!\implies F=ma$

$\\ \sf{:}\!\implies Acceleration=\dfrac{F}{m}$

$\\ \sf{:}\!\implies Acceleration=\dfrac{8}{0.25}$

$\\ \sf{:}\!\implies Acceleration=32m/s^2$