Answer:
AB = 16 Units
Step-by-step explanation:
In the given figure, CD is the diameter and AB is the chord of the circle.
Since, diameter of the circle bisects the chord at right angle.
Therefore, AE = 1/2 AB
Or AB = 2AE...(1)
Let the center of the circle be given by O. Join OA.
OA = OD = 10 (Radii of same circle)
Triangle OAE is right triangle.
Now, by Pythagoras theorem:
![OA^2 = AE^2 + OE^2 \\10^2 = AE^2 + 6^2 \\100= AE^2 + 36\\100-36 = AE^2 \\64= AE^2 \\AE = \sqrt{64}\\AE = 8 \\\because AB = 2AE..[From \: equation\: (1)] \\\therefore AB = 2\times 8\\\huge \purple {\boxed {AB = 16 \: Units}}](https://tex.z-dn.net/?f=%20OA%5E2%20%3D%20AE%5E2%20%2B%20OE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E10%5E2%20%3D%20AE%5E2%20%2B%206%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E100%3D%20%20AE%5E2%20%2B%2036%5C%5C%3C%2Fp%3E%3Cp%3E100-36%20%3D%20AE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E64%3D%20AE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3EAE%20%3D%20%5Csqrt%7B64%7D%5C%5C%3C%2Fp%3E%3Cp%3EAE%20%3D%208%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Cbecause%20AB%20%3D%202AE..%5BFrom%20%5C%3A%20equation%5C%3A%20%281%29%5D%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Ctherefore%20AB%20%3D%202%5Ctimes%208%5C%5C%3C%2Fp%3E%3Cp%3E%5Chuge%20%5Cpurple%20%7B%5Cboxed%20%7BAB%20%3D%2016%20%5C%3A%20Units%7D%7D%20)
9514 1404 393
Answer:
a = 6, b = 12, c = 6, d = 6√3
Step-by-step explanation:
The two triangles are the "special" triangles.
The 45-45-90 triangle has side lengths in the ratios 1 : 1 : √2.
The 30-60-90 triangle has side lengths in the ratios 1 : √3 : 2.
Then ...
c : a : 6√2 = 1 : 1 : √2 ⇒ c = a = 6
and ...
a : d : b = 1 : √3 : 2 ⇒ d = 6√3 and b = 12 . . . (since a=6)
The lengths are ...
a = 6, b = 12, c = 6, d = 6√3
Fill in m and n with numbers then minus by one
Answer:
-48 and -49
Step-by-step explanation:
n + n + 1 = -97
2n + 1 = -97
2n + 1 - 1 = -97 - 1
2n = -98
2n/2 = -98/2
n = -49
-49 + 1 = -48
-49, -48
