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3 years ago

Help please?!??!??!?!?!

Chemistry

1 answer:

GalinKa [24]3 years ago

3 0

Answer:

Explanation:

Matter is anything that has weight and occupies space. Weight is synonymous to mass

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adam wants to investigate the strengths of different acids and alkalis. He has 2 different acid solutions and 2 different alkali

SCORPION-xisa [38]

Answer:

The strength of an acid or alkali depends on the degree of dissociation of the acid or alkali in water. The degree of dissociation measures the percentage of acid molecules that ionise when dissolved in water. He could use universal indicators or litmus paper for this.

Explanation:

(See answer for the explanation)

5 0

2 years ago

Which of the following best describes the impact of glaciers upon the surface of the earth?

Ahat [919]

Answer:

D. All of the above

Explanation:

Because all of these have something to do with how glaciers are affecting the planet.

6 0

3 years ago

A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti

MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

$H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_3H_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL$

Putting values in above equation, we get:

$2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M$

Thus the molarity of the malonic acid solution is 0.08335 M

5 0

3 years ago

A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH

Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5 → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0

2 years ago

Design a synthesis of 2-bromo-1-chloro-4-nitrobenzene from benzene or any mono-substituted benzene. Part 1 out of 6 choose the b

Oxana [17]

2-bromo-1-chloro-4-nitrobenzene is being synthesized in following sequence:

Step 1: Chlorination of Benzene:

This is Halogenation reaction of benzene. In this step benzene is reacted with Chlorine gas in the presence of lewis acid (i.e. FeCl₃). This results in the formation of Chlorobenzene as shown in red step below.

Step 2: Nitration of Chlorobenzene:

The chlorine atom on benzene has a ortho para directing effect. Therefore, the nitration of chlorobenzene will yield para nitro chlorobenzene as shown in blue step below.

Step 3: Bromination of 1-chloro-4-nitrobenzene:

In this step bromination is done by reacting bromine in the presence of lewis acid. The chlorine being ortho para directing in nature and nitro group being meta directing in nature will direct the incoming Br⁺ (electrophile) to the desired location. Hence, 2-bromo-1-chloro-4-nitrobenzene is synthesized in good yield.

6 0

3 years ago