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Alenkinab [10]
4 years ago
7

Which of the following cannot be determined from the spectrum of a star?

Physics
2 answers:
lozanna [386]4 years ago
7 0

Answer:

The chemicals in the core of the star

Explanation:

The spectrum of a star is of its atmosphere. The absorption or emission spectrum that is obtained indicates the chemical composition of the star's atmosphere. The peak wavelength obtained indicates the surface temperature of the star (using Wien's-Displacement Law). The shift in the spectrum indicates the motion of the star. If there is blueshift, it indicates that it is moving towards us where as if there is a red shift, it indicates that it is moving away from us.

grigory [225]4 years ago
4 0
The event that cannot be determined from the spectrum of a star is that the <span>chemicals in the atmosphere of the star</span>
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Say you want to make a sling by swinging a mass M of 2.3 kg in a horizontal circle of radius 0.034 m, using a string of length 0
ycow [4]

Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

F_c=m\frac{v^2}{r}  (1)

m: mass object = 2.3 kg

r: radius of the circular orbit = 0.034 m

v: tangential speed of the object

However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

K=\frac{1}{2}mv^2

You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:

v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}

you replace this value of v in the equation (1). Also, you replace the values of r and m:

F_c=(2.3kg)(\frac{11.3m^2/s^2}{0.034})=764.41N

hence, the tension in the string must be T =  Fc = 764.41 N

5 0
3 years ago
A cannon is fired from a castle wall at some unknown height above the ground. The cannonball leaves the cannon with speed 30.0m/
Sauron [17]

Answer:

Part a)

t = 3.85 s

Part b)

h = 72.67 m

Part C)

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = -22.77 m/s

Explanation:

Part a)

Horizontal speed of the cannon

v = 30.0 m/s

angle of projection

\theta = 30^o

now we have

horizontal speed = v_x = vcos30 = 30 cos30 =25.98 m/s

vertical speed = v_y = vsin30 = 30 sin30 = 15 m/s

now the time taken by it to cover the distance 100 m from the wall

x = v_x t

100 = 25.98 t

t = 3.85 s

Part b)

Since it hits the ground in the same time

so the height of the castle is given as

h = \frac{1}{2}gt^2

h = \frac{1}{2}(9.81)(3.85^2)

h = 72.67 m

Part C)

At highest point of the projection

the vertical component of the velocity will become zero

so we will have

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

so we have

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = v_i + at

v_y = 15 - 9.81(3.85)

v_y = -22.77 m/s

Part e)

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3 years ago
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KengaRu [80]

It is the heart

if not im sorry

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3 years ago
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What is the distance of a car travels is its velocity is 30 mph and its time is 2 hours ?
Alborosie

Answer:

distance = 60 miles

Explanation:

3 0
2 years ago
At a construction site, the site manager notices that a crane takes 20 seconds to lift a 500kg steel beam up to a height of 15 m
posledela
The work done is equal to the change in potential energy which is:
P.E = mgh
P.E = 500 x 9.81 x 15
P.E = 73,575 J

Power = work / time
Power = 73,575 / 20
Power = 3,700 Watts
5 0
4 years ago
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