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Alexeev081 [22]
4 years ago
7

Calculate the moment of inertia and the rotational kinetic energy for the following objects spinning about a central axis (in un

its of Joules): a solid sphere with a mass of 200 grams and a radius of 5.0 cm rotating with an angular speed of 2.5 rad/sec. a thin spherical shell with a mass of 200 grams and a radius of 5.0 cm rotating with an angular speed of 2.5 rad/sec. a solid cylinder with a mass of 200 grams and a radius of 5.0 cm rotating with an angular speed of 2.5 rad/sec. a hoop with a mass of 200 grams and a radius of 5.0 cm rotating with an angular speed of 2.5 rad/sec.
Physics
1 answer:
Helga [31]4 years ago
6 0

Answer:

a) K = 6.25 10⁻⁴ J , b)  K = 10.41  10⁻⁴ J , c)  K = 7.81 10⁻⁴ J , d)  K = 15.625 10⁻⁴ J

Explanation:

The moment of inertia is

         I = ∫ r² dm

For high symmetry bodies it is tabulated.

The rotational kinetic energy is

         K = ½ I w²

Let's calculate the values ​​of the given bodies

a) solid sphere

         I = 2/5 M R²

         I = 2/5 0.200 0.05²

         I = 2 10⁻⁴ kg m²

        K = ½ 2 10⁻⁴ 2.5²

        K = 6.25 10⁻⁴ J

b) spherical shell

        I = 2/3 M R²

        I = 2/3 0.200 0.05²

        I = 3.33 10⁻⁴ kg m²

        K = ½ 3.33 10-4 2.5²

        K = 10.41  10⁻⁴ J

c) solid cylinder

        I = ½ M R²

        I = ½ 0.200 0.05²

        I = 2.5 10⁻⁴ kg m²

       K = ½ 2.5 10-4 2.5²

       K = 7.81 10⁻⁴ J

d) hoop

       I = M R²

       I = 0.200 0.05²

       I = 5 10⁻⁴ kg m²

      K = ½ 5 10⁻⁴ 2.5²

      K = 15.625 10⁻⁴ J

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Answer:

Moment of Inertia, I = 0.016 kgm²

Explanation:

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