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dem82 [27]
3 years ago
8

Juan is standing on the street. An ambulance moves toward him and then passes by. What best describes the pitch that Juan heats?

(A )the pitch remains constant as the ambulance moves toward and then away from Juan. (B) the pitch increases and decreases in a repeated pattern as the ambulance passes Juan. (C) the pitch drops to a lower pitch once the ambulance passes by Juan. (D) the pitch increases to a higher pitch once the ambulance passes by Juan.
Physics
1 answer:
Artemon [7]3 years ago
7 0

(C) The pitch will drop once the ambulance passes by Juan. The reason for this is because of the doppler effect.

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Test your prediction through calculation for the situations of the clay bob and the bouncy ball. Assume each has a mass of 100 g
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Answer:

a) Δp = -2.0 kgm / s,  b)   Δp = -4 kg m / s

Explanation:

In this exercise the change in moment of a ball is asked in two different cases

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         Δp = p_f - p₀

         Δp = 0 - m v₀

         Δp = - 0.100 20

         Δp = -2.0 kgm / s

b) in this case we have a bouncing ball, this is an elastic collision, as the gate is fixed it can be considered an object of infinite mass, therefore the final speed of the ball has the same modulus of the initial velocity, but address would count

         v_f = - v₀

        Δp = p_f -p₀

        Δp = m v_f - m v₀

        Δp = m (v_f -v₀)

        Δp = 0.100 (-20 - 20)

        Δp = -4 kg m / s

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2 years ago
A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What
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The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

a_{c} =\frac{v^{2} }{r}

Where a_{c} is the centripetal acceleration

v is the velocity

and r is the radius

From the given information

v = 12 \ m/s

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Therefore,

a_{c} =\frac{12^{2} }{30}

a_{c} =\frac{144 }{30}

a_{c} = 4.8\ m/s^{2}

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

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