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3 years ago

What is 2.5 × 104 × 3 × 102?

1 answer:

5 0

I assume these are scientific notation thus 10^x not 10x
first multiply all numbers together
so 2.5*10^4*3*10^2
or 25000*300
so you get 7500000.0
move the decimal to 7.5
which is 6 places
the answer is c 7.5*10^6

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What is the frequency of radiation whose wavelength is 2.40 x 10-5 cm?

S_A_V [24]

<span>To begin, the formula for finding frequency when wavelength is known is "f = c / w" when c is the constant velocity (3 * 10^8 m/s). To convert the wavelength into a common form (m/s), it will have to be multiplied by 10^-2. This leaves the equation as "f = 3.0 * 10^8 / (2.4 * 10^-5 * 10^-2), or 2.4 * 10^-7. This gives 1.25 * 10^15 m/s as the frequency.</span>

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3 years ago

An object with a higher temperature can have less thermal energy than an object

Anna [14]

It’s true, because it also depends on things like mass. Higher temperature but less mass< Lower temperature but more mass.

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3 years ago

The speed of a wave changes depending on the temperature of the medium. What do you think is the reason for this?

igor_vitrenko [27]

Answer: Because of the different wave speed from light and sound. Explanation: There is a major difference between the speed wave of light and sound, light travels at 186, 282 miles per second, and sound can travel at different speeds and its significantly slower so it is easier to measure it

Explanation:

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3 years ago

You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice

Galina-37 [17]

The stopping distance is 143.1 m

Explanation:

First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:

$\sum F =ma$

where

$\sum F = F_f = -0.14 N$ is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)

m = 0.12 kg is the mass of the puck

a is the acceleration

Solving for a,

$a=\frac{\sum F}{m}=\frac{-0.14}{0.12}=-1.17 m/s^2$

The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v^2-u^2=2as$

where:

v = 0 is the final velocity (the puck comes to a stop)

u = 18.3 m/s is the initial velocity

$a=-1.17 m/s^2$ is the acceleration

s is the stopping distance

And solving for s, we find

$s=\frac{v^2-u^2}{2a}=\frac{0-(18.3)^2}{2(-1.17)}=143.1 m$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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3 years ago

6. Why does sound travel faster through a steel bar than through a swimming pool filled with water?

Lady_Fox [76]

I understand that sound travels faster in water then in air. Water is a liquid, and air is gas.

Water still has the ability to roll the molecules over each other (so water can flow), it has some flexibility.

But I do not understand how a solid that is inflexible can make sound waves travel faster then in a flexible liquid.

In fact, sound waves travel over 17 times faster through steel than through air.

Sound waves travel over four times faster in water than it would in air.

3 0

3 years ago