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3 years ago

Four students measure the mass of a standard mass that has an accepted value of 150.0 g. They post their results in a table.

Physics

1 answer:

Eddi Din [679]3 years ago

4 0

Explanation:

This problem seeks to ensure that the student comprehends the meaning of precision and accuracy.

These two key terms are used to express how reliable experimental values obtained are.

Precision is the ability to consistently reproduce a result.
Accuracy is the nearness of the measure value to the true value.
The different between the measured and true values gives the error in the result.

In the problem given, the most accurate reading would be one that has value close to the standard mass of 150g. Any student that reports this value would be reported as accurate.

The precise reading would be for the student that is able to repeatedly produce the same kind of values. This is irrespective of whether the values are close to the true value or not.

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Based on the calculations, the ratio of the intensity of Ir to Ip is equal to 50.12.

<h3>How to find the ratio of the intensity?</h3>

Let the intensity of the power mower be Ip.

Let the intensity of the rock music be Ir.

Mathematically, sound intensity level can be calculated by using this formula:

$\beta = 10 log(\frac{I}{I_{ref}} )$

<u>Where:</u>

I is the intensity of the sound.

Making I the subject of formula, we have:

I = Io × $10^{\frac{\beta }{10} }$

For Ip, we have:

Ip = Io × $10^{\frac{104 }{10} }$

Ip = Io × $10^{10.4}$

For Ir, we have:

Ir = Io × $10^{\frac{121 }{10} }$

Ir = Io × $10^{12.1}$

Now, we can find the ratio of the intensity:

Ir/Ip = Io × $10^{12.1}$ /Io × $10^{10.4}$

Ir/Ip = $10^{12.1}$ / $10^{10.4}$

Ir/Ip = $10^{12.1 -10.4}$

Ir/Ip = $10^{1.7}$

Ir/Ip = 50.12.

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Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

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Explanation:

From the question we are told that:

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