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OLga [1]
2 years ago
11

What is the natural frequency (wo) of a circuit that has an inductor of 0.048 henery's, and a capacitor of 0.0004 farads?

Physics
1 answer:
adell [148]2 years ago
4 0

Answer:

The natural frequency will be 228.11 rad/sec

Explanation:

We have given Inductance L = 0.048 Henry

And the capacitance C = 0.0004 farad

We have to find natural frequency

When only inductor and capacitor is present in the circuit then it is known as LC circuit and  Natural frequency of LC circuit is given by \omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec

So the natural frequency will be 228.21

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You apply a force of 500 N to 150 N/m. how much does it stretch? Show the equation you are using, plus the values into the equat
jolli1 [7]

Answer:

3.33m

Explanation:

Given parameters:

Force applied  =500N

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Unknown:

Amount of stretch or extension  = ?

Solution:

To solve this problem use the expression below:

    F  = k e

F is the force applied

k is the elastic constant

e is the extension

  So;

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harkovskaia [24]

Answer:

ionized particles from the sun.

* interactions in radiation belts.

* the friction of the planet in the solar wind

q = +9 10⁵ C

Explanation:

Due to being made up of matter, the planet Earth has a series of positive and negative charges, in general these charges should be balanced and the net charge of the planet should be zero, but there are several phenomena that introduce unbalanced charges, for example:

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This creates that the planet has a net electrical load

         

We can roughly calculate the charge of the planet

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             q = E r² / k

let's calculate

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2 years ago
Question 2 10
ss7ja [257]
B Ik it all just know who they’ll you
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