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3 years ago

What is the natural frequency (wo) of a circuit that has an inductor of 0.048 henery's, and a capacitor of 0.0004 farads?

Physics

1 answer:

adell [148]3 years ago

4 0

Answer:

The natural frequency will be 228.11 rad/sec

Explanation:

We have given Inductance L = 0.048 Henry

And the capacitance C = 0.0004 farad

We have to find natural frequency

When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by $\omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec$

So the natural frequency will be 228.21

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An occupant of a car can survive a crash if the deceleration during the crash is less than 30 g. Calculate the force on a 64 kg

forsale [732]

The force on a 64 k person decelerating on that rate would be :

F = ma

F = 64 kg x 30 x 9.8

= 18816 N

Hope this helps

6 0

3 years ago

The index of refraction for a certain type of glass is 1.641 for blue light and 1.603 for red light. When a beam of white light

exis [7]

Answer:

The angle between the emergent blue and red light is $0.566^{o}$

Explanation:

We have according to Snell's law

$n_{1}sin(\theta _{i})=n_{2}sin(\theta _{r})$

Since medium from which light enter's is air thus $n_{1}=1$

Thus for blue incident light we have

$1\times sin(40.05)=1.641\times sin(\theta _{rb})\\\\\therefore \theta _{rb}=sin^{-1}(\frac{sin(40.05)}{1.64})\\\\\theta _{rb}=23.10$

Similarly using the same procedure for red light we have

$1\times sin(40.05)=1.603\times sin(\theta _{rr})\\\\\therefore \theta _{rr}=sin^{-1}(\frac{sin(40.05)}{1.603})\\\\\theta _{rr}=23.66^{o}$

Thus the absolute value of angle between the refracted blue and red light is

$|23.66-23.10|=0.566^{o}$

6 0

3 years ago

The heat required to melt a piece of copper is (82 x 10 ^5 J). The heat of fusion of copper is (2.05×10 ^5 J/ kg). What is the m

Musya8 [376]

Answer:

Explanation:

Givens

Heat of Fusion = 2.05 * 10^5 J / kg watch the units.

Heat to actually melt the copper = 82 10^5 J

Formula

Mass of copper = Heat / Heat of Fusion

Solution

Mass of copper = 82*10^5 J / (2.05 * 10^5 J / kg)

Mass of copper = 40 kg

Notice that the kg is in the denominator of the second fraction. The rules of fractions would tell you the 1/1 / / 1 /kg . You take the right fraction and turn it upside down and multiply. 1 / 1 * kg/1 = 1* kg / 1*1 which is just kg.

Answer 40 kg of copper

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2 years ago

What can you conclude about plastic and copper from the observations given above?

ipn [44]

What are the "observations above" in this question?

5 0

3 years ago

A laser produces 20.0 mW of red light. In 1 hour, the laser emits 2.29 X 10^20 photons. What is the wavelength of the laser?

Butoxors [25]

Using Planck's equation,

E = nhc / λ

Also, Power = Energy / time
E = 20 x 10⁻³ x 60 x 60
E = 108 J

108 = (2.29 x 10²⁰ x 6.63 x 10⁻³⁴ x 3 x 10⁸) / λ
λ = 4.22 x 10⁻⁷ m

8 0

3 years ago