Answer:
(a) r = 6.26 * 10⁻⁷cm
(b) r₂ = 6.05 * 10⁻⁷cm
Explanation:
Using the sedimentation coefficient formula;
s = M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle
s = M ( 1 - Vρ) / N*6πnr
making r sbjct of formula, r = M (1 - Vρ) / N*6πnrs
Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s
r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)
r = 6.26 * 10⁻⁷cm
b. Using the formula r₂/r₁ = s₁/s₂
s₂ = 0.035 + 1s₁ = 1.035s₁
making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁
r₂ = 6.3 * 10⁻⁷cm / 1.035
r₂ = 6.05 * 10⁻⁷cm
Answer is: the number of ions produced in the dissociation of aluminium fluoride is 4.
<span>
Chemical dissociation of aluminium fluoride in
water:
AlF</span>₃(aq) →
Al³⁺(aq) + 3F⁻(aq).<span>
There are four ions, one aluminium cation and
three fluoride anions.
Aluminium has oxidation +3, because it lost
three electrons, to have electron configuration as noble gas neon and fluorine has oxidation -1, because it gain one electron to </span>have electron configuration as noble gas neon.
1 elements
2 they have same number of valence electrons
3 period
Find volume of pillow
L=78cm
B=55cm
H=25cm
Now
Mass=5.5kg
Density of water=1000kg/m^3
As it is less than density of water it will float on water
