Answer: 1) only a salt and water
An acid and base reacts together to undergo neutralization to form salt and water.
where HCl is an acid and NaOH is a base to form salt (NaCl) and water 
.
Answer: 2) The formula of the hydrogen ion is often written as 
.
All acids dissociate in water to give ions.
Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.
Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.
Answer: 4) A conjugate acid base pair transfers hydrogen ion.
Here 
accepts a proton and thus act as a base and the corresponding 
is its conjugate acid.
Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.
and 
is a acid which accepts proton and thus acts as base to form conjugate acid .
<u>Answer:</u> The enthalpy of the reaction is coming out to be 2231 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_{(product)}]-\sum [n\times \Delta H^o_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(1\times \Delta H^o_{(C_4H_8(g))})]-[(1\times \Delta H^o_{(C_4H_4(g))})+(2\times \Delta H^o_{(H_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H%5Eo_%7B%28C_4H_8%28g%29%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_%7B%28C_4H_4%28g%29%29%7D%29%2B%282%5Ctimes%20%5CDelta%20H%5Eo_%7B%28H_2%28g%29%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times (-2755))]-[(1\times (-286))+(2\times (-2341))]\\\\\Delta H^o_{rxn}=2213kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-2755%29%29%5D-%5B%281%5Ctimes%20%28-286%29%29%2B%282%5Ctimes%20%28-2341%29%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D2213kJ)
Hence, the enthalpy of the reaction is coming out to be 2231 kJ.
Answer:
The correct answer is hydrogen.
Explanation:
Stars in the main sequence will remain in the main sequence as long as their cores contain hydrogen atoms. This is because main sequence stars run on the hydrogen atoms within their core to prevent them from falling to the force of gravity. Once these hydrogen atoms run out, the star is no longer considered a main sequence star, gravity takes hold, and the star collapses.
I also agree it's b they move randomly
