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Rus_ich [418]
3 years ago
5

Mandy has three stuffed animals. Two of the animals have a mass of 200 grams each, and the third one has a mass of 250 grams. Wh

at is the combined mass of the three stuffed animals?
Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0
<span>650 grams is 0.65 kilograms but that says of a kilogram kinda confusing on how they word it so i cant be 100% but that is what i would put</span>

Crank3 years ago
4 0
Hello! 

Alright so Mandy has 3 animals total. Two of them weigh 200g and the last one weighs 250g. 

We can solve this by adding all of the animals masses together. 

Animal 1+ Animal 2+ Animal 3= total mass of the animals in grams

200+200+250= 650g

Don't forget to record the unit of measurement (g) in your answer, hope this helps! 

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What’s the area of the figure below?
TEA [102]

Answer:

482.5 ft^2.

Step-by-step explanation:

The figure can be regarded as a rectangle with a triangle cut out of one corner.

The base of the triangle = 25-20 = 5 in and the height = 20 - 13 = 7 in.

The required area = area of rectangle - area of triangle

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5 0
3 years ago
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An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

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6 0
3 years ago
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Answer:

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Mars2501 [29]
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6 0
3 years ago
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