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Mumz [18]
3 years ago
8

A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 m

/s. By the time it reached the buoy, it was going 10 m/s. What was the average velocity of the boat? -3.33 m/s2 -1.11 m/s +1.11 m/s +3.33 m/s
Physics
1 answer:
castortr0y [4]3 years ago
7 0
Distance=20m
time=18s
Initial velocity=0m/s
Final velocity=10m/s

The equation we use to find average velocity is v=d/t (average velocity=distance/time)

V=20m/18s
V (average velocity)=1.11m/s
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the balls would move closer to each other

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a baseball player is dashing toward home plate with a speed of 200 feet per hour. When he decides to hit the dirt. he slides for
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To solve this problem we will use the kinematic formula for the final velocity.


V_f_x = V_0_x + a_xt


The final speed is 0 at the moment the player stops.


The time until it stops is 1.3 s


The initial speed is 200 feet / s  Note (check the speed units in the problem statement, 200ft / s is very much and 200ft / h is very small)

Then, we clear the formula.


a_x = \frac{(Vfx-V0x)}{t}\\ a_x = \frac{(0-200)}{1.3}\\ a_x = -153.5 ft / s ^ 2

Because the player is slowing down, the acceleration goes in the opposite direction to the player's movement, and that is why it is negative.



To answer part b) we use the following formula.


Vf ^ 2 = Vo ^ 2 + 2a * (x_2 - x_1)\\\\ (x_2 - x_1)= \frac{(V_f ^ 2-V_0 ^ 2)}{2a}\\\\ (x_2 - x_1)= \frac{(0-200 ^ 2)}{- 2 * 153.5}\\\\ (x_2 - x_1)= 130.29 feet

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3 years ago
Why is it very difficult for astronomers to find objects like planets and asteroids?
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A 350-N child is in a swing that is attached to a pair of ropes 2.10 m long. Find the gravitational potential energy of the chil
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Answer:

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Explanation:

The gravitational power energy is

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a) Rope is horizontal

The height in this case is the same length of the rope

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b) when the angle is 34º

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    y = 2.10 (1- cos 34)

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c) in this case this point coincides with the reference system

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