Question

A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 m/s. By the time it reached the buoy, it was going 10 m/s. What was the average velocity of the boat? -3.33 m/s2 -1.11 m/s +1.11 m/s +3.33 m/s

Answer 1

Distance=20m
time=18s
Initial velocity=0m/s
Final velocity=10m/s

The equation we use to find average velocity is v=d/t (average velocity=distance/time)

V=20m/18s
V (average velocity)=1.11m/s