A 93 kg zebra is traveling 13 m/s east. What is the zebra’s momentum?

If it takes a planet 2.8 Ã— 108 s to orbit a star with a mass of 6.2 Ã— 1030 kg, what is the average distance between the planet

Shtirlitz [24]

The average distance between the planet and the star is:

R=9.36*10^11 m

Orbital velocity v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

As was already said, Earth is located roughly 150 million kilometres (93 million miles) from the Sun on average. It is 1 AU. Mars is on our fictitious football field's three-yard line. On average, the distance between the Sun and the red planet is around 142 million miles (228 million kilometres).

Learn more about average distance:

brainly.com/question/18366547

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The complete question is ''If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 10^30 kg, what is the average distance between the planet and the star? 1.43 × 10^9 m 9.36 × 10^11 m 5.42 × 10^13 m 9.06 × 10^17 m''.

4 0

1 year ago

A proton initially at rest is accelerated by a uniform electric field. The proton moves 4.76 cm in 1.10 x 10^-6 s. Find the volt

iVinArrow [24]

Answer:

The voltage drop through which the proton moves is 39.1 V.

Explanation:

Given that,

Distance = 4.76 cm

Time $t=1.10\times10^{-6}\ s$

We need to calculate the acceleration

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

Where, s = distance

a = acceleration

t = time

Put the value in the equation

$4.76\times10^{-2}=\dfrac{1}{2}\times a \times(1.10\times10^{-6})^2$

$a=\dfrac{2\times 4.76\times10^{-2}}{(1.10\times10^{-6})^2}$

$a=7.87\times10^{10}\ m/s^2$

We need to calculate the voltage drop

Using formula of electric field

$F=qE$

$F = q\dfrac{V}{d}$ ....(I)

Using newton's second law

$F = ma$ ....(II)

Put the value of F in equation (I) from equation (II)

$ma=\dfrac{qV}{d}$

$V=\dfrac{mad}{q}$

Where, q = charge

a = acceleration

d = distance

m= mass of proton

Put the value into the formula

$V=\dfrac{1.67\times10^{-27}\times7.87\times10^{10}\times4.76\times10^{-2}}{1.6\times10^{-19}}$

$V=39.1\ V$

Hence, The voltage drop through which the proton moves is 39.1 V.

8 0

3 years ago

3. Which statement would best describes the motion of the object graphed here?

Karo-lina-s [1.5K]

Answer:

It is B most likely

Explanation:

7 0

3 years ago

Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.1×109 electrons from one disk to the

Bad White [126]

Answer:

$d = 0.018 m$

Explanation:

Charge on the plates of the capacitor due to transfer of electrons is given as

$Q = Ne$

here we know that

$N = 2.1 \times 10^9$

so we have

$Q = (2.1 \times 10^9)(1.6 \times 10^{-19})$

$Q = 3.36 \times 10^{-10} C$

now we have electric field between the plates is given as

$E = \frac{Q}{A\epsilon_0}$

here we have

$1.5 \times 10^5 = \frac{3.36 \times 10^{-10}}{A(8.85 \times 10^{-12})}$

$A = 2.53 \times 10^{-4} m^2$

now we have

$A = \frac{\pi d^2}{4}$

$2.53 \times 10^{-4} = \frac{\pi d^2}{4}$

$d = 0.018 m$

3 0

3 years ago

When selecting a material for a measuring temperature, we use what sort of properties?

ehidna [41]

<span>Temperature is measured via thermometer. It also measures the hotness or coldness of a system or surroundings. It is based on the physical and chemical properties of a fluid such as thermal expansion of fluids (fluids expand when heated and compress at a low temperature) by studying the kinetic energy of the molecules of the fluid.</span>

7 0

3 years ago