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2 years ago

11

A 93 kg zebra is traveling 13 m/s east. What is the zebra’s momentum?

1 answer:

Harlamova29_29 [7]2 years ago

3 0

Equation: Mass x Velocity = Momentum

Answer: 93 x 13 = 1,209

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Most electricity comes from the burning of

yKpoI14uk [10]

Answer:

(A) Fossil Fuels

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3 years ago

Read 2 more answers

svetlana [45]

Part A:
( 5,000 : 100 ) * 6 = 300 lit.
300 lit. * 1.066 Euros/ lit. = 318.9 Euros
1 Euro = 1.20 USD
318.9 * 1.20 = 382.68 USD

Part B :
6 lit./100 km = 0.06 lit/1 km
1 gal = 3.7853 lit.
1 mile = 1.609344 km
0.06 : 3.7853 = 0.01585
... = 0.01585 gal / 1 km / * 1.609344
= 0.0255 gal/mile

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3 years ago

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Straw polls are___. A. scientifically based B. representative samples C. biased sampling D. cluster samples

soldi70 [24.7K]

Straw polls are considered to be a form of biased sampling. An example of a straw poll is an unofficial vote like who you would like to be the President without actually casting your ballot.

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2 years ago

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

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2 years ago

WGVU-AM is a radio station that serves the Grand Rapids, Michigan area. The main broadcast frequency is 1480kHz. At a certain di

Yuki888 [10]

Answer:

a

$\lambda = 202.7 \ m$

b

$w = 9.3 *10^{6} \ rad/s$

c

$k = 0.031 m^{-1}$

d

$E_{max} = 9.0 *10^{-3} \ V/m$

Explanation:

From the question we are told that

The frequency of the radio station is $f= 1480 \ kHz = 1480 *10^{3}\ Hz$

The magnitude of the magnetic field is $B = 3.0* 10^{-11} \ T$

Generally the wavelength is mathematically represented as

$\lambda = \frac{c}{f}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

So

$\lambda = \frac{3.0 *10^{8}}{ 1480 *10^{3}}$

=> $\lambda = 202.7 \ m$

Generally the angular frequency is mathematically represented as

$w = 2 \pi * f$

=> $w = 2 * 3.142 * 1480 *10^{3}$

=> $w = 9.3 *10^{6} \ rad/s$

Generally the wave number is mathematically represented as

=> $k = \frac{2 \pi }{\lambda}$

=> $k = \frac{2 * 3.142 }{ 202.7}$

=> $k = 0.031 m^{-1}$

Generally the amplitude of the electric field at this distance from the transmitter is mathematically represented as

$E_{max} = c * B$

=> $E_{max} = 3.0 *10^{8} * 3.0* 10^{-11}$

=> $E_{max} = 9.0 *10^{-3} \ V/m$

3 0

2 years ago