All categories

3 years ago

Ways to increase friction??

Physics

1 answer:

natima [27]3 years ago

8 0

Create a “rougher” or more adhesive point of contact,Press the two surfaces together harder., etc.

You might be interested in

A 26.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 11.0 m th

frozen [14]

Answer:

18 m/s

Explanation:

Force is given by mass × acceleration

F = ma

a = F/m

For the first 11.0 m, there is no friction. Hence, the constant force is applied fully on the crate. The acceleration is

a = 225/26.0 m/s²

By the equation of motion, v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance travelled.

Using the values for the first part of the motion,

v² = 0² + 2 × 8.65 × 11.0

v = 13.8 m/s

This is the initial velocity for the second part of the motion. This part has friction of coefficient 0.20.

The frictional force = 0.20 × weight = 0.20 × 26.0 × 9.8 = 50.96 N

The effective force moving the crate in the second motion = 225 - 50.96 N = 174.04 N

This gives an acceleration of 174.04/26.0 = 6.69 m/s².

Using parameters for the equation of motion, v² = u² + 2as

v² = 13.8² + 2 × 6.69 × 10 = 324.24

v = 18 m/s

8 0

4 years ago

A 2.0kg rocket is traveling straight up. What force muse be applied to the rocket for it to move at a constant velocity?

Yuliya22 [10]

A equal force it always has to be equal

5 0

4 years ago

Two grocery carts have the same initial total momentum. The two carts collide, and now cart B has a greater final velocity.

Angelina_Jolie [31]

Answer:

Cart B has a smaller mass

Explanation:

I may be wrong but if mass is decreased then acceleration increases, and if velocity increases then acceleration increases so my logic is that if mass decreases then velocity increases.

7 0

3 years ago

Read 2 more answers

An object exhibits SHM with an angular frequency w = 4.0 s-1 and is released from its maximum displacement of A = 0.50 m at t =

vivado [14]

Explanation:

It is given that,

Angular frequency, $\omega=4\ s^{-1}$

Maximum displacement, A = 0.5 m at t = 0 s

We need to find the time at which it reaches its maximum speed. Firstly, we will find the maximum velocity of the object that is exhibiting SHM.

$v_{max}=A\times \omega$

$v_{max}=0.5\times 4$

$v_{max}=2\ m/s$ ............(1)

Acceleration of the object, $a=\omega^2A$

$a=4^2\times 0.5$

$a=8\ m/s^2$ ...............(2)

Using first equation of motion we can calculate the time taken to reach maximum speed.

$v=u+at$

$t=\dfrac{v-u}{a}$

$t=\dfrac{2-0}{8}$

t = 0.25 s

So, the object will take 0.25 seconds to reach its maximum speed. Hence, this is the required solution.

4 0

3 years ago

What must be true if a waves wavelength is short ?

dem82 [27]

Answer: So, if the wavelength of a light wave is shorter, that means that the frequency will be higher because one cycle can pass in a shorter amount of time. ... That means that longer wavelengths have a lower frequency. Conclusion: a longer wavelength means a lower frequency, and a shorter wavelength means a higher frequency!

4 0

3 years ago