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Arte-miy333 [17]
3 years ago
8

Ways to increase friction??

Physics
1 answer:
natima [27]3 years ago
8 0
Create a “rougher” or more adhesive point of contact,Press the two surfaces together harder., etc.
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Discuss how does a Van de Graaff generator works?​
Svetllana [295]

Answer:

How does a Van de Graaff generator works?

A Van de Graaff generator pulls electrons from the Earth, moves them along a belt and stores them on the large sphere. These electrons repel each other and try to get as far away from each other as possible, spreading out on the surface of the sphere. ... It provides a convenient path for electrons to move to the ground.

source-

scienceworld.ca

5 0
3 years ago
Alaskan Natives often eat whale blubber while other groups of people typically do not. This is an example of __________. A. food
8_murik_8 [283]

Answer:

This is an example of Learned preferences.

Explanation:

Alaskan natives are divided into five major groups viz: aleuts, southern eskimos, northern eskimos, interior indians and coastal indians. Although the five groups all have similar ethnic similarities, they occupy different geographical locations in Alaska. The alaska natives have overtime had to adapt to certain conditions largely because of their environment.

6 0
4 years ago
Read 2 more answers
Two point sources produce waves of the same wavelength that are in phase. At a point midway between the sources, you would expec
Rasek [7]

Answer:

Constructive Interference.

Explanation:

Constructive Interference.

Definition:

Two waves meet in such a way their highs(Crests) combine to form a new waves whose magnitude is the sum of magnitude of combining waves.

Since two waves have same wavelength and are in phase so when they combine they well form a way which has the magnitude equal to the sum of the magnitude of both waves.

Reasons why it is Constructive Interference:Waves

  • Have Same wavelength
  • Are in phase (Can have phase difference of 2π
  • Have crests aligned with each other (Appear at same point)
5 0
3 years ago
A student solving a physics problem for the range of a projectile has obtained the expression r= v20sin(2θ)g where v0=37.2meter/
DedPeter [7]

Formula of range is given by

R = \frac{v_o^2 sin2\theta}{g}

here given that

v_0=37.2m/s

θ=14.1∘

g=9.80m/s^2

now by above equation

R = \frac{37.2^2 sin2*14.1}{9.80}

R = 66.7 m

so range will be 66.1 m

5 0
3 years ago
Read 2 more answers
ASK YOUR TEACHER A 2.0-kg mass swings at the end of a light string with the length of 3.0 m. Its speed at the lowest point on it
Nadya [2.5K]

Answer:

  K_b = 78 J

Explanation:

For this exercise we can use the conservation of energy relations

starting point. Lowest of the trajectory

        Em₀ = K = ½ mv²

final point. When it is at tea = 50º

        Em_f = K + U

        Em_f = ½ m v_b² + m g h

where h is the height from the lowest point

        h = L - L cos 50

        Em_f = ½ m v_b² + mg L (1 - cos50)

energy be conserve

        Em₀ = Em_f

         ½ mv² = ½ m v_b² + mg L (1 - cos50)

         K_b = ½ m v_b² + mg L (1 - cos50)

let's calculate

          K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)

          K_b = 36 +42.0

          K_b = 78 J

4 0
3 years ago
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