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Citrus2011 [14]
3 years ago
6

If 25 g of NH3, and 96 g of H2S react according to the following reaction, what is the

Chemistry
1 answer:
jeyben [28]3 years ago
4 0

25 g of NH₃ will produce 47.8 g of (NH₄)₂S​

<u>Explanation:</u>

2 NH₃ + H₂S ----> (NH₄)₂S​

Molecular weight of NH₃ = 17 g/mol

Molecular weight of (NH₄)₂S​ = 68 g/mol

According to the balanced reaction:

2 X 17 g of NH₃ produces 68 g of (NH₄)₂S​

1 g of NH₃ will produce \frac{68}{34} g of (NH₄)₂S​

25g of NH₃ will produce \frac{65}{34} X 25 g of (NH₄)₂S​

                                     = 47.8 g of (NH₄)₂S​

Therefore, 25 g of NH₃ will produce 47.8 g of (NH₄)₂S​

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What is the percent error for the experiment if the actual density is
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Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 2.49g/mL

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We have

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We have the final answer as

<h3>40.96 %</h3>

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4 0
3 years ago
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7 0
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Describe what happens to the mass number and the atomic number of a nuclide during alpha decay.
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4 0
3 years ago
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Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

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To determine:

Concentration at time t = 300 s i.e. [a]_{t}

Calculations:

The second order rate equation is:

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substituting for k,t and [a] we get:

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Hence the concentration of 'a' after t = 5min is 0.020 M



7 0
3 years ago
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