Answer:
Water applied to the surface of a relatively dry soil infiltrates quickly due to the affinity of the soil particles for water. As time passes and the soil becomes wet, the force of gravity becomes the dominant force causing water to move.
Explanation:
The sign of the entropy change, ΔS, for the following processes include:
- I2 (s) + ½ Cl2 (g) ← → ICl (g) - positive
- 3 Ag (s) + 4 HNO3 (aq) → 3AgNO3 (aq) + NO (g) + 2 H2O (l) - positive
- Cl2 (g) → Cl2 (l) - negative
- C5H12 (g) + 8 O2 (g) → 5 CO2 (g) + 6 H2O (l) - negative
What is Entropy?
This is referred to the degree of randomness or disorderliness of a system and is denoted as S.
Entropy change is usually positive when solid or liquid reactant is converted into gas product and vice versa.
Read more about Entropy here brainly.com/question/419265
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That would be the proton. The number of protons in the nucleus determine which element it is and its properties.
Yea, i think it's a shopping mall
Answer:
to the right (products side)
Explanation:
The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:
a A + b B → c C + d D
The equilibrium constant expression is:
![K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%5BD%5D%5E%7Bd%7D%20%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%20%7D)
A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).
Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.
Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.
