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3 years ago

Siya saw two elements X and Y. Element X is shiny and hard, while element Y is dull and

Chemistry

1 answer:

ExtremeBDS [4]3 years ago

3 0

Answer:element x

Explanation:because element x is shiny and hard and that's a property of metals and metals are good conductors of heat and electricity

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Natural gas is primarily composed of ________. natural gas is primarily composed of ________. methane sulfur dioxide nitrogen ox

umka21 [38]

Natural gas is primarily composed of methane (CH4)

Natural gas is a naturally occurring hydrocarbon mixture which is primarily composed of Methane(CH4), but it also contains ethane,propane and heavier hydrocarbon. In addition it contain small amount of nitrogen, carbon dioxide,hydrogen sulfide and traces amount of water.

7 0

3 years ago

A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur

dsp73

Answer:

12.8 g of $O_{2}$ must be withdrawn from tank

Explanation:

Let's assume $O_{2}$ gas inside tank behaves ideally.

According to ideal gas equation- $PV=nRT$

where P is pressure of $O_{2}$ , V is volume of $O_{2}$ , n is number of moles of $O_{2}$ , R is gas constant and T is temperature in kelvin scale.

We can also write, $\frac{V}{RT}=\frac{n}{P}$

Here V, T and R are constants.

So, $\frac{n}{P}$ ratio will also be constant before and after removal of $O_{2}$ from tank

Hence, $\frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}$

Here, $\frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm}$ and $P_{after}=17atm$

So, $n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol$

So, moles of $O_{2}$ must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of $O_{2}$ = 32 g/mol

So, mass of $O_{2}$ must be withdrawn = $(32\times 0.40)g=12.8g$

7 0

3 years ago

PLEASE HELP ME If a radioactive substance has an initial mass of 50 grams

Yuri [45]

Answer: $3.125\ g$

Explanation:

Given

Initial mass $A_o=50\ g$

half-life is $T_{\frac{1}{2}}=5\ years$

At any time the left amount is given by

$A=A_o2^{-\dfrac{t}{T_{\frac{1}{2}}}}\\\\\text{Insert the values}\\\\A=50\cdot 2^{-\dfrac{20}{5}}\\\\A=50\cdot 2^{-4}\\\\A=\dfrac{50}{16}\\\\A=3.125\ g$

3 0

3 years ago

What is the molarity of a solution made by diluting 0.025L of 6.0 M HCl until

Nadusha1986 [10]

Answer:

Explanation:

Use the dilution equation: M1V1 = M2V2

M1 = 6.0 M

V1 = 0.025 L

M2 = ?

V2 = 1.75 L

(6.0 M)(0.025 L) = M2(1.75 L)

Solve for M2 --> M2 = 0.086 M HCl

3 0

3 years ago

7. With solutions of strong acids and strong bases, the word strong refers to

Mumz [18]

Answer:

C. Degree of ionization

Explanation:

The strength of an acid or a base is determined by how many H+/H3O+ or OH- ions are dissociated in solution. Therefore, it's describing the degree of ionization.

Example: HCl is a strong acid because in water it will pretty much 100% dissociate into H+ and Cl- ions.

4 0

3 years ago