![\left[\begin{array}{ccc}22&18\end{array}\right]\times\left[\begin{array}{cccc}5&18&32&40\\25&40&38&12\end{array}\right]\\\\=\left[\begin{array}{cccc}22\cdot5+18\cdot25&22\cdot18+18\cdot40&22\cdot32+18\cdot38&22\cdot40+18\cdot12\end{array}\right]\\\\=\left[\begin{array}{cccc}560&1116&1388&1096\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D22%2618%5Cend%7Barray%7D%5Cright%5D%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%2618%2632%2640%5C%5C25%2640%2638%2612%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D22%5Ccdot5%2B18%5Ccdot25%2622%5Ccdot18%2B18%5Ccdot40%2622%5Ccdot32%2B18%5Ccdot38%2622%5Ccdot40%2B18%5Ccdot12%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D560%261116%261388%261096%5Cend%7Barray%7D%5Cright%5D)
second question:
January: 32 · 22 + 38 · 18 = 704 + 684 = 1388
December: 18 · 22 + 40 · 18 = 396 + 720 = 1116
1388 - 1116 = 272
Answer: $272.
Answer:
bus = 43
van 12
Step-by-step explanation:
This can be solved using simultaneous equations
Let v represent the number of students that a van carries
Let b represent the number of students that a bus carries
the following equations can be derived from the question
3v + 2b = 122 eqn 1
5v + 3b = 189 eqn 2
Multiply eqn 1 by 5 and eqn 2 by 3
15v + 10b = 610 eqn 3
15v + 9b = 567 eqn 4
Subtract equation 4 from 3
b = 43
Substitute for b in equation 1
3v + 2(43) = 122
solve for v
v = 12
Let the missing number be x
r= x/50= 450/x
x^2 = 22500
x = 150
Hi!
When you add a negative number, you really just subtract it. So let's solve this.
Convert the mixed numbers into improper fractions.

Solve
434 - 351 = 83

The sign of this fraction is positive
Hope this helps! :)
-Peredhel
What’s the question that u need an answer to