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Varvara68 [4.7K]
3 years ago
14

Write a hypothesis about the effect a change in temperature will have on the volume of a gas.

Physics
2 answers:
Licemer1 [7]3 years ago
7 0
The colder the more likely it is to become a liquid
horsena [70]3 years ago
3 0
Hypothesis:
As long as I keep the gas in the same container, a change in
temperature will have no effect on the volume of the gas.

Exception:
If I make it TOO cold, then the gas it will change to liquid, and
this hypothesis won't apply.
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What is the difference between panda and rhino?​
olya-2409 [2.1K]

Answer:

Explanation:

The difference between panda and rhino are :

<u>panda</u>

1. The giant panda, also known as the panda bear, is a bear native to South Central China

2. Their thick black and white fur equips them for life in cool forests

<u>Rhino</u>

1. There are 5 species of rhino.

2. Rhinos have poor vision

7 0
3 years ago
Read 2 more answers
The launching velocity of a missile is 20.0 m/s, and it is shot at 53º above the horizontal. What is the vertical component of t
Lyrx [107]

Given that

Velocity of missile (v) = 20 m/s ,

Angle of missile (Θ) = 53°

Determine ,   Vertical component  = v sin Θ

                                                        = 20 sin 53°

                                                        = 15.97 m/s

6 0
4 years ago
A single insulated duct flow experiment using air operating at steady-state is performed in a lab. One measurement location (Sta
weqwewe [10]

Answer:

a) -0.0934 kJ/kg. K

b) The direction of flow is from right to left.

Explanation:

A free flow diagram of the horizontal insulated duct is as shown below.

NOW,

Let assume that the direction of flow is from left to right and consider the following relation for the entropy rate balance equation for a control volume as:

\frac{\sigma_{cv}}{m}= (s_2-s_1) \geq  0 \ \ \ -------> \ \ \ 1

Now; if the value for this relation is greater than zero; then we conclude that our assumption is correct.

If the value is less than zero; then we conclude that the assumption is wrong.

Then, the flow is said to be  in the opposite direction

Formula for the change in specific entropy can be calculated as:

s_2-s_1 = s^0(T_2) - s^0(T_1)-R \ In ( \frac{P_2}{P-1}) \ \ \  ------->  \ \ \ 2

where;

s_1, s_2 , s^0(T_2), s^0(T1) are specific entropies

R = universal gas constant

P_1 = pressure at location 1

P_2 = pressure at location 2

We obtain the specific properties of air at temperature at T_1 = (67°C + 273)K = 340 K from the table A-22 ( Ideal gas properties of air)

s^0(T1) = 1.8279 kJ/kg.K

We also obtain the specific properties of air at temperature T_2 = 22°C + 273) K = 295 K

From the table A- 22

s^0(T_2) = 1.68515 kJ/kg . K

R = \frac{8.314 kJ}{28.97 kg.K}

P_1 = 0.95 bar

P_2 = 0.8 bar

Now replacing our values  into equation (2) from above; we have;

s_2-s_1 = s^0(T_2) -s^0(T_1)-R \ In (\frac{P_2}{P_1} )

s_2-s_1 = 1.68515 -1.8279-\frac{8.314}{28.97}  \ In (\frac{0.8}{0.95} )

s_2-s_1 = 1.68515 -1.8279+ 0.0493

s_2-s_1 =-0.0934 \  kJ/kg.K

Equating our result to equation (1)

s_2-s_1 \geq 0\\-0.0934 \leq 0

Therefore , our assumption is wrong and the direction of flow is said to be from right to left.

We therefore conclude that the direction of flow is from right to left.

3 0
3 years ago
A student pulls a cart across the floor with a force of 45 N. If the cart travels 10 m, how much work does the cart do on the st
bixtya [17]
I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.  

6 0
3 years ago
What is the unique geological feature found on Mercury surface?
Cloud [144]

Answer:

The surface of Mercury has landforms that indicate its crust may have contracted. They are long, sinuous cliffs called lobate scarps. These scarps appear to be the surface expression of thrust faults, where the crust is broken along an inclined plane and pushed upward.

Explanation:

I hope this helps a little bit.

3 0
3 years ago
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