determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if per
1 answer:
Answer:
-0.383 m
Explanation:
Diameter of cylinder = 4m therefore r = 2
height of cylinder ( H ) = 4 m
specific gravity = 0.6 ( assumed )
depth of immersion = 'h'
<u>Determine the metacentric height </u>
weight of cylinder in water = water displaced
= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h
= 0.6 * 4 = h
∴ h = 2.4 m
hence the depth of center of buoyancy from free space = h /2 = 1.2 m
The metacentric height can be calculated using the formula below
Gm = Io / Vsubmerged - BG
attached below is the remaining solution
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Answer:
B.The force of friction between the block and surface will decrease.
Explanation:
The force of friction is given by
where is the coefficient of friction and
is the normal force.
When the student pulls on the block with force at an angle
, the normal force on the block becomes
and hence the frictional force becomes
.
Now, as we increase ,
increases which as a result decreases the normal force
, which also means the frictional force decreases; Hence choice B stands true.
<em>P.S: Choice D is tempting but incorrect since the weight </em><em> is independent of the external forces on the block. </em>