Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.
Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.
We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
Answer:
• riding on a Ferris wheel whose entrance and exit are the same
• walking around the block, starting from and ending at the same house
• running exactly one lap around a racetrack
Explanation:
Displacement simply means the.change in position of an object. In a situation whereby the initial and final position are thesame, the displacement will be zero.
The statements that describe a situation with a displacement of zero include:
• riding on a Ferris wheel whose entrance and exit are the same
• walking around the block, starting from and ending at the same house
• running exactly one lap around a racetrack
If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspeed will Increase and true altitude will increase.
<h3>What is Altitude?</h3>
This refers to the vertical elevation of a body and is the measurement of the height above the sea or ground level. An airplane's altitude is directly proportional to the airspeed as long as the power is constant.
This means that increase in airspeed will lead to an increase in altitude and vie versa. This is the reason why as it runs fast, it can be observed that it begins to elevate.
Read more about Altitude here brainly.com/question/1159693
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Answer:
1.5X10^-4C
Explanation:
Expression for the electric force between the two charges is given by -
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = unknown
F=25N
q2 = 1.9x10^-6 C
r = 0.32 m
Substitute the given values in the above expression -
25=9x10^9 *(q1) * 1.9 x10^ -6/ (0.32m)^2
25= 17,100* (q1)/ 0.1024
multiply both sides by 0.1024 to get rid of the denominator
2.56=17,100*(q1)
Divide both sides by 17,100 to isolate q1
q1=1.5x10^-4C
