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Gala2k [10]
2 years ago
15

The diagram shows a skydiver at different points of her jump. At what point would her

Physics
1 answer:
8_murik_8 [283]2 years ago
6 0
I’m pretty sure it’s B! :)
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Consider going around a horizontal turn to the right. If the coaster suddenly slipped off the track, what path would it follow?
Svetlanka [38]

Answer:

Explanation: It would go straight because objects in motion stay in motion and it would stay the same direction

5 0
2 years ago
Development occurs:
Alex73 [517]

Answer:

D

Explanation:

:(

4 0
2 years ago
tony walks at an average speed of 70m/min from home to school. If the difference between his home and the school is 2100 m, how
finlep [7]
Answer. 30 minutes
Explanation. If he walks 70 m in one minute how long will it take him to walk 2,100 m. Well, this is a simple division problem (you could also use a ratio box).
2100/70= 30. Hope this helps, let me know if it’s correct so others can use it :)
Good luck.
5 0
2 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
3. A 900N mountain climber scales a
Umnica [9.8K]

Answer:

<h2>135,000 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 900 × 150

We have the final answer as

<h3>135,000 J</h3>

Hope this helps you

4 0
2 years ago
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