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garri49 [273]
3 years ago
6

John has just graduated from State University. He owes $35,000 in college loans, but he does not have a job yet. The college loa

n company has agreed to give John a break on a deferred-payment plan that works as follows. John will not have to repay his loan for 5 years. During this “grace period” the loan obligation will compound at 4% per year. For the next 5 years, a monthly payment will be required, and the interest rate will be 0.5% per month. What will be John’s monthly payment over the 60-month repayment period?
Engineering
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

The correct response is "821.88". A further explanation is given below.

Explanation:

According to the question,

The largest amount unresolved after five years would have been:

= 35000\times (\frac{F}{P}, 4 \ percent,5 )

= 35000\times 1.216 7

= 42584.50

Now,

time (t) will be:

= 5\times 12

= 60 \ monthly \ payments

So, monthly payment will be:

= 42582.85\times (\frac{A}{P}, 0.5 \ percent,60 )

= 42584.50\times 0.0193

= 821.88

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The absolute pressure in water at a depth of 9 m is read to be 185 kPa. Determine: a. The local atmospheric pressure b. The abso
ser-zykov [4K]

Answer:

a)Patm=135.95Kpa

b)Pabs=175.91Kpa

Explanation:

the absolute pressure is the sum of the water pressure plus the atmospheric pressure, which means that for point a we have the following equation

Pabs=Pw+Patm(1)

Where

Pabs=absolute pressure

Pw=Water pressure

Patm= atmospheric pressure

Water pressure is calculated with the following equation

Pw=γ.h(2)

where

γ=especific weight of water=9.81KN/M^3

H=depht

A)

Solving using ecuations 1 y 2

Patm=Pabs-Pw

Patm=185-9.81*5=135.95Kpa

B)

Solving using ecuations 1 y 2, and atmospheric pressure

Pabs=0.8x5x9.81+135.95=175.91Kpa

8 0
4 years ago
Define escape velocity​
irakobra [83]
The lowest velocity which a body must have in order to escape the gravitational attraction of a particular planet or other object.
4 0
3 years ago
3. Given the Taylor series expansion for sin x = x − x3/ 3! + x5/5! − x7/7! . Write a program that takes in an arbitrary integer
katen-ka-za [31]

Answer:

clc

clear

x = input('type value of angle in degrees:\n');

x = x*pi/180; %convverting fron degree to radian

sin_x = x; %as first term of taylor series is x

E = 1; %just giving a value of error greater than desired error

n = 0;

while E > 0.000001

previous = sin_x;

n = n+1;

sin_x = sin_x + ((-1)^n)*(x^(2*n+1))/factorial(2*n+1);

E = abs(sin_x - previous); %calculating error

end

a = sprintf('sin(x) = %1.6f',sin_x);

disp(a)

Explanation:

8 0
4 years ago
A(n) 500-Ω and a(n) 2000-Ω resistor are connected in series with a 12-V battery. Part A What is the voltage across the 2000-Ω re
Alona [7]

Answer:

9.6 V

Explanation:

Total resistance (Rt) = R1 + R2 = 500 + 2000 = 2500 ohm

V = IRt

I = V/Rt = 12/2500 = 4.8×10^-3 A

Voltage across the 2000 ohm resistor (V2) = IR2 = 4.8×10^-3 × 2000 = 9.6 V

3 0
4 years ago
What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C
Anvisha [2.4K]

Answer:

331809.5gallon/hr or 92.16gallon/s

Explanation:

What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C

convert 9.4 acre to inches we have=5.896*10^7

How to calculate Peak runoff discharge

1. take the dimension of the roof

2. multiply the dimension by the n umber of inches of rainfall

3. Divide by 231 to get gallon equivalence (because 1 gallon = 231 cubic inches)

5.896*10^7*1.3

7.66*10^7 cubic inches/hr

1 gallon=231 cubic inches

7.66*10^7 cubic inches=331809.5gallon/hr or 92.16gallon/s

this is gotten by converting 1 hr to seconds

331809.5gallon/hr /3600s=92.16gallon/s

8 0
3 years ago
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