Answer:
a)Patm=135.95Kpa
b)Pabs=175.91Kpa
Explanation:
the absolute pressure is the sum of the water pressure plus the atmospheric pressure, which means that for point a we have the following equation
Pabs=Pw+Patm(1)
Where
Pabs=absolute pressure
Pw=Water pressure
Patm=
atmospheric pressure
Water pressure is calculated with the following equation
Pw=γ.h(2)
where
γ=especific weight of water=9.81KN/M^3
H=depht
A)
Solving using ecuations 1 y 2
Patm=Pabs-Pw
Patm=185-9.81*5=135.95Kpa
B)
Solving using ecuations 1 y 2, and atmospheric pressure
Pabs=0.8x5x9.81+135.95=175.91Kpa
The lowest velocity which a body must have in order to escape the gravitational attraction of a particular planet or other object.
Answer:
clc
clear
x = input('type value of angle in degrees:\n');
x = x*pi/180; %convverting fron degree to radian
sin_x = x; %as first term of taylor series is x
E = 1; %just giving a value of error greater than desired error
n = 0;
while E > 0.000001
previous = sin_x;
n = n+1;
sin_x = sin_x + ((-1)^n)*(x^(2*n+1))/factorial(2*n+1);
E = abs(sin_x - previous); %calculating error
end
a = sprintf('sin(x) = %1.6f',sin_x);
disp(a)
Explanation:
Answer:
9.6 V
Explanation:
Total resistance (Rt) = R1 + R2 = 500 + 2000 = 2500 ohm
V = IRt
I = V/Rt = 12/2500 = 4.8×10^-3 A
Voltage across the 2000 ohm resistor (V2) = IR2 = 4.8×10^-3 × 2000 = 9.6 V
Answer:
331809.5gallon/hr or 92.16gallon/s
Explanation:
What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C
convert 9.4 acre to inches we have=5.896*10^7
How to calculate Peak runoff discharge
1. take the dimension of the roof
2. multiply the dimension by the n umber of inches of rainfall
3. Divide by 231 to get gallon equivalence (because 1 gallon = 231 cubic inches)
5.896*10^7*1.3
7.66*10^7 cubic inches/hr
1 gallon=231 cubic inches
7.66*10^7 cubic inches=331809.5gallon/hr or 92.16gallon/s
this is gotten by converting 1 hr to seconds
331809.5gallon/hr /3600s=92.16gallon/s