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adoni [48]
3 years ago
13

Find the density of a sample with a mass of 2.56 g and a volume of

Chemistry
1 answer:
Ksju [112]3 years ago
6 0

Answer:

<h3>The answer is 0.79 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 2.56 g

volume = 3.25 mL

We have

density =  \frac{2.56}{3.25}  \\  = 0.78769230...

We have the final answer as

<h3>0.79 g/mL</h3>

Hope this helps you

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Write a balanced net ionic equation for the following reaction. BaCI2(aq)+H2SO4(aq) -&gt; BaSO4(s)+HCI (aq)
Sever21 [200]
Ba²⁺ + 2Cl⁻ + 2H⁺ + SO₄²⁻ = BaSO₄ (precipitate) + 2H⁺ + 2Cl⁻
Ba²⁺ + SO₄²⁻ = BaSO₄
4 0
3 years ago
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Discussion Questions 1. Given the equilibrium equation for a general reaction, A + B  C + D, explain what happens to the reacta
ANTONII [103]

Answer:The equilibrium constant for a given reaction is [concentration of products]/[concentration of reactants].

Explanation:

Equilibrium constant=[concentration of products]/[concentration of reactants]

The concentration of reactant  molecules is maximum at time 0 and it  decreases as the reaction proceeds, The concentration of product molecules increases.At equilibrium the concentration of reactants and products are equal.

All the changes would occur in accordance with the LeChateliers principle.

For the given reaction the following changes would occur:

a When CO is removed from the reaction mixture so the reaction would shift towards right that is in forward direction as we are decreasing the concentration of CO so the system would try to increase the concentration of CO and that can happen by more production of CO.

b Since the above reaction is an endothermic reaction so when we would be adding heat to the system that is when we would increase the temperature  the reaction would shift forwards as  more heat energy is absorbed by reactants  to form more products.

c When more CO₂ is added so more amount of reactants are added to the system so the system would try to decrease the amount of reactants that is CO₂ and hence more amount of products would be formed.The reaction would shift in forward direction.

d Since  this reaction is endothermic in nature so when we remove the heat from reaction hence even less amount of heat is present in the system and so the reaction shift in backward direction as the reaction cannot proceed without enough amount of heat.

8 0
3 years ago
Hydrogen bonds form between neighboring water molecules because of ________. A. electron transfer B. electron sharing C. the vis
Oduvanchick [21]

Answer:

Answer is B.

Explanation:

Hydrogen bonds forms when hydrogen atom is attracted towards oxygen atom of other water. A proton is shared by two ion electrons pair in which oxygen atom is partially negatively charged while hydrogen atom is partially positively charged.

7 0
2 years ago
How can Newton's Third Law of Motion be used to explain why it is difficult to walk on a slippery surface, such as ice?
Olenka [21]
E ground pushes you forward. But that interaction is friction. Reduce friction and it doesn't matter how strong your legs are, the surface is incapable of pushing you accordingly. The coefficient of static friction is very low so it is easy to slide your foot rather than push.
6 0
2 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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