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kherson [118]
3 years ago
7

Janice needs to have a gastro-intestinal study. So she is given 375 mg of radiocontrast dye containing Barium-142. The half-life

of Ba-142 is 10.6 minutes and its decay is followed by -ray. After one half -life, of Ba-142 remains . After 31.8 minutes , of Ba-142 remains . After half-lives, 11.7 mg of Ba - 142 remains . After minutes , 0.366 mg of Ba - 142 remains. Finally, after approximately 3.5 hours - half-lives , only 0.000358 mg remains . The dye is no longer visible to the Xray and Janice's study is over .
Chemistry
1 answer:
katovenus [111]3 years ago
5 0

After one half life, 188mg

46.9 mg of Ba-142

After 5 half lives

After 106 minutes

20 half lives , only 0.000358 mg remains

Hope this helps

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An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about 4.4x 10 m/s Calculate the
otez555 [7]

The question is incomplete, here is the complete question:

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about 4.4\times 10^6m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of helium. Write your answer as a percentage of the average speed, and round it to 2 significant digits

<u>Answer:</u> The percentage of average speed is 41 %

<u>Explanation:</u>

We are given:

Radius of helium atom = 31 pm = 31\times 10^{-12}m    (Conversion factor:  1m=10^{12}pm )

So, diameter of helium atom = (2\times r)=(2\times 31\times 10^{-12})=64\times 10^{-12}m

The diameter of the atom will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

\Delta x.\Delta p=\frac{h}{2\pi}

where,

\Delta x = uncertainty in position = d = 64\times 10^{-12}m

\Delta p = uncertainty in momentum  = m\Delta v

m = mass of electron = 9.1095\times 10^{-31}kg

h = Planck's constant = 6.627\times 10^{-34}kgm^2/s^2

Putting values in above equation, we get:

64\times 10^{-12}m\times 9.1095\times 10^{-31}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 64\times 10^{-12}m\times 9.1095\times 10^{-31}kg}=1.81\times 10^6m/s

To calculate the percentage of average speed, we use the equation:

\text{Percentage of the average speed}=\frac{\text{Uncertainty in velocity}}{\text{Average orbital speed}}\times 100

We are given:

Average orbital speed = 4.4\times 10^6m/s

Putting values in above equation, we get:

\text{Percentage of the average speed}=\frac{1.81\times 10^6m/s}{4.4\times 10^6m/s}\times 100\\\\\text{Percentage of the average speed}=41.\%

Hence, the percentage of average speed is 41 %

3 0
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Chemical energy is the energy stored in atoms that deal with the strictures etc. What determines this is the <span>thermodynamic.</span>
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State two properties of sulphur that makes it possible to extract using the frasch process​
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Explanation:

sulphur has a low melting point.

sulphur has a low boiling point thus it can be extracted by pumping hot water which turns it ito solution form

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A sample of nitrogen gas contains 9.46x10^23 atoms of nitrogen. How much nitrogen is expressed in grams? round your answer to th
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  • No of. atoms=9.46×10^23

We know

\boxed{\star{\sf No\;of\:atoms=No\:of\: moles\times Avagadro's\: number}}

\\ \rm\Rrightarrow No\:of\;moles=\dfrac{No\:of\:atoms}{Avagadro's\:no}

\\ \rm\Rrightarrow No\:of\:moles =\dfrac{9.46\times 10^{23}}{6.022\times 10^{23}}

\\ \rm\Rrightarrow No\:of\:moles=1.6mol

Again

\boxed{\star{\sf Mass=Molar\:mass\times No\:of\:moles}}

\\ \rm\Rrightarrow Mass=1.6(14)

\\ \rm\Rrightarrow Mass=22.4g

6 0
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