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Veseljchak [2.6K]
4 years ago
6

What are three a ways orchids attract insects to spread their flower pollen

Chemistry
1 answer:
Licemer1 [7]4 years ago
7 0
Orchids attract insects many different ways depending on the insect that they attract. Orchids attract flies by using the smell of rotten flesh. Gross right? Anyways another way they can attract insects is because of the shape of their petals. Some males insects think that their petals look like female insects and the male insect then lands on the petal and spreads pollen onto the flower Hope this helped - Ashlynn
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How many hours are in 1987 seconds. Please explain
blagie [28]

Just divide!

60 seconds = 1 min

60 mins = 1 hour

1987 seconds divided by 60 seconds = 33.11 minutes

Your answer would be 33 minutes and 11 seconds

8 0
3 years ago
Which of the following would introduce bias into an experiment?
Nastasia [14]
I believe it is A or D. since "<span>Scientific bias is the assumption that a </span>theory<span> is true or false without evidence one way or another, or the attempt to dismiss or discourage research efforts to confirm or deny the </span>theory<span> "</span>
5 0
4 years ago
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A substance with two or more different types of atoms chemically bonded together is called....
Slav-nsk [51]

Answer:

D

Explanation:

7 0
3 years ago
What is true about the combustion of water?
miv72 [106K]

Answer:

C

Explanation:

Spontaneous combustion is a type of combustion which occurs by self-heating (increase in temperature due to exothermic internal reactions), followed by thermal runaway (self-heating which rapidly accelerates to high temperatures) and finally, ignition.

7 0
3 years ago
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A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l
madreJ [45]

Explanation:

From first source, kinetic energy (K.E_{1}) ejected is 1 eV and wavelength of light is \lambda.

From second source, kinetic energy (K.E_{2}) ejected is 4 eV and wavelength of light is \frac{\lambda}{2}.

Relation between work function, wavelength, and kinetic energy is as follows.

                   K.E = \frac{hc}{\lambda} - \phi

where,        h = Plank's constant = 6.63 \times 10^{-34} J.s

                   c = speed of light = 3 \times 10^{8} m/s

Also, it is known that 1 eV = 1.6 \times 10^{-19} J

Therefore, substituting the values in the above formula as follows.

  • From first source,

                      K.E_{1} = \frac{hc}{\lambda} - \phi  

            1 eV = 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi    

    1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi        ........... (1)

  • From second source,

                  K.E_{2} = \frac{hc}{\lambda} - \phi  

          4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi        

                 6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi        ........... (2)        

Now, divide equation (2) by 2. Therefore, it will become

       {6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}

                3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}   ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

                 1.6 \times 10^{-19} = \frac{\phi}{2}

                    \phi = 3.2 \times 10^{-19}

                          = 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0
4 years ago
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