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S_A_V [24]
3 years ago
7

What is the mass, in grams, of 1.30×1021 molecules of aspirin, C9H8O4?

Chemistry
2 answers:
jeyben [28]3 years ago
6 0

The mass of  1.30 \times {\text{1}}{{\text{0}}^{{\text{21}}}}\;{\text{molecules}} of aspirin is \boxed{0.389{\text{ g}}}.

Further Explanation:

Avogadro’s number is a mathematical number that determines the number of atoms or molecules in one mole of the substance. The value of Avogadro’s number is {\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{units}}. These units can either be atoms or molecules.

There are {\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}} in one mole of aspirin. Therefore the number of moles in 1.30 \times {\text{1}}{{\text{0}}^{{\text{21}}}}\;{\text{molecules}} of aspirin can be calculated as follows:

 \begin{aligned}{\text{Moles of aspirin}} &= \left( {1.30 \times {\text{1}}{{\text{0}}^{{\text{21}}}}\;{\text{molecules}}} \right)\left( {\frac{{1{\text{ mol}}}}{{6.022 \times {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}}}}} \right)\\&= 2.159 \times {10^{ - 3}}{\text{ mol}}\\\end{aligned}

The formula to calculate the moles of aspirin is as follows:

{\text{Moles of aspirin}} = \dfrac{{{\text{Mass of aspirin}}}}{{{\text{Molar mass of aspirin}}}}          …… (1)                                                  

Rearrange equation (1) for the mass of aspirin.

{\text{Mass of aspirin}} = \left( {{\text{Moles of aspirin}}} \right)\left( {{\text{Molar mass of aspirin}}} \right)     …… (2)                            

The molar mass of aspirin \left( {{{\text{C}}_{\text{9}}}{{\text{H}}_{\text{8}}}{{\text{O}}_{\text{4}}}} \right) can be calculated as follows:

  {\text{Molar mass of }}{{\text{C}}_{\text{9}}}{{\text{H}}_{\text{8}}}{{\text{O}}_{\text{4}}} &= \left[ \begin{aligned}9\left({{\text{Atomic mass of C}}} \right)+ \hfill\\8\left( {{\text{Atomic mass of H}}} \right) +  \hfill\\4\left({{\text{Atomic mass of O}}} \right) \hfill\\\end{aligned}  \right]                                             …… (3)

The atomic mass of C is 12.01 g.

The atomic mass of H is 1.008 g.

The atomic mass of O is 15.99 g.

Substitute these values in equation (3).

 \begin{aligned}{\text{Molar mass of }}{{\text{C}}_{\text{9}}}{{\text{H}}_{\text{8}}}{{\text{O}}_{\text{4}}} &= \left[ {9\left( {{\text{12}}{\text{.01 g}}} \right) + 8\left( {{\text{1}}{\text{.008 g}}} \right) + 4\left( {{\text{15}}{\text{.99 g}}} \right)} \right] \\&=\left[ {108.09{\text{ g}} + 8.064{\text{ g}} + 63.96{\text{ g}}} \right]\\&= 180.114{\text{ g/mol}}\\\end{aligned}

The number moles of aspirin is 2.159 \times {10^{ - 3}}{\text{ mol}}.

The molar mass of aspirin is 180.114 g/mol.

Substitute these values in equation (2).

 \begin{aligned}{\text{Mass of aspirin}} &= \left( {2.159 \times {{10}^{ - 3}}{\text{ mol}}} \right)\left( {\frac{{{\text{180}}{\text{.114 g}}}}{{1{\text{ mol}}}}} \right)\\&= {\text{0}}{\text{.38887 g}}\\&\approx {\text{0}}{\text{.389 g}}\\\end{aligned}

Therefore the mass of aspirin is 0.389 g.

Learn more:

  1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603
  2. Calculate the moles of ions in the solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Chapter: Mole concept

Subject: Chemistry

Keywords: aspirin, molar mass, atomic mass, C, H, O, C9H8O4, 0.389 g, mass of aspirin, 180.114 g/mol, 12.01 g, 1.008 g, 15.99 g, moles, molecules, 1.30*10^21 molecules, 6.022*10^23 molecules, atoms, Avogadro’s number.

stealth61 [152]3 years ago
3 0

0.39 grams

<h3>Further explanation</h3>

<u>Given that:</u>

1.30 x 10²¹ molecules of aspirin C₉H₈O₄

<u>Question:</u>

The mass, in grams

<u>The Process:</u>

Firstly, we prepare the molar mass of aspirin C₉H₈O₄.

Relative atomic mass (in rounding to integers):

  • C = 12 g/moles
  • H = 1 g/moles
  • O = 16 g/moles

In aspirin, there are 9 carbon atoms, 8 hydrogen atoms, and 4 oxygen atoms. Therefore the molar mass is given by

\boxed{(12 \times 9) + (1 \times 8) + (16 \times 4) = 180 \ g/moles}

Secondly, we calculate the moles of 1.30 x 10²¹ molecules of aspirin.

Remember this, one mole contains 6.02 x 10²³ molecules, which is called The Avogadro's number.

Let's convert 1.30 x 10²¹ molecules to the number of moles.

\boxed{ \ The \ moles = 1.31 \times 10^{21} \ molecules \times \frac{1 \ mole}{6.02 \times 10^{23} \ molecules} \ }

We get \boxed{ \ 2.176 \times 10^{-3} \ moles \ }

Finally, we calculate the mass in grams.

\boxed{ \ The \ mass = 2.176 \times 10^{-3} \ moles \times 180 \ \frac{g}{moles} \ }

Thus the mass of 1.30 x 10²¹ molecules of aspirin C₉H₈O₄ is 0.39 grams.

- - - - - - -

<u>Quick Steps</u>

\boxed{\boxed{ \ The \ mass = 1.30 \times 10^{21} \ molecules \times \frac{1 \ mole}{6.02 \times 10^{23} \ molecules} \times \frac{180 \ grams}{1 \ mole} \ }}

<h3>Learn more</h3>
  1. Conservation of mass  brainly.com/question/9473007
  2. The molality and mole fraction of water brainly.com/question/10861444  
  3. The chemical formula for nitrobenzene brainly.com/question/2861241

Keywords: the mass, in grams, molecules, avogadro's numbers, moles, molar mass, relative atomic mass

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