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Ghella [55]
4 years ago
13

Graphing inequalities k < -3​

Mathematics
1 answer:
NikAS [45]4 years ago
7 0

Step-by-step explanation: So when graphing this problem, we start at -3 on our number line with an open dot because <em>k</em> is less than but not equal to -3. I have shown this in the image attached below.

We then draw an arrow going to the left to represent all number less than -3.

Finally, we put our answer in set notation which is shown below.

{K: k < -3}

All this means is that if we take any number less than -3, this will be a solution for the inequality <em>k < -3</em>.

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Find EXACT area of regular hexagon (keep in radical form)
pickupchik [31]

Answer:

1. 24\sqrt{3}   2. 162\sqrt{2}

Step-by-step explanation:

1. The area of a hexagon is A = \frac{3\sqrt{3} }{2} a^{2}

Here our a is 4, so plugging in 4 to our equation gives \frac{3\sqrt{3} }{2} (4^{2}) which simplifies to 24\sqrt{3}

2. The area of an octagon is 2\sqrt{2} r^{2}

Here our r is 9, so plugging in 9 to our equation gives 2\sqrt{2} (9^{2} ) which simplifies to 162\sqrt{2}

6 0
4 years ago
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
The scale factor of two similar hexagons is 5:12. The smaller hexagon has an area of 24 square units. What is the area of the la
ASHA 777 [7]

Answer: 138.24\ \text{square units}

Step-by-step explanation:

Given

The scale factor of two similar hexagons is 5:12.

The smaller hexagon has an area of 24 square units

we know, the ratio of two similar figures is equal to the square of the scale factor.

Suppose the area of the larger hexagon is A

\therefore \dfrac{24}{A}=\left[\dfrac{5}{12}\right]^2\\\\\Rightarrow A=\left[\dfrac{12}{5}\right]^2\times 24\\\\\Rightarrow A=138.24\ \text{square units}

3 0
3 years ago
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