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SCORPION-xisa [38]
3 years ago
13

Suppose the total momentum of two masses before a collision is 100 kg m/s. What is the total momentum of the two masses after th

ey collide? A. 0 kg m/s B. 50 kg m/s C. 100 kg m/s D. 200 kg m/s Is the answer D?
Physics
1 answer:
soldier1979 [14.2K]3 years ago
4 0
No, momentum is conserved so:
momentum before=momentum after
it is C. 100 kg m/s
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An insulated beaker with negligible mass contains 0.250 kg of water at 75.0C. How many kilograms of ice at -20.0C must be droppe
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Answer:

The amount of kilograms of ice at -20.0°C that must be dropped into the water to make the final temperature of the system 40.0°C = 0.0674 kg

Explanation:

Heat gained by ice in taking the total temperature to 40°C = Heat lost by the water

Total Heat gained by ice = Heat used by ice to move from -20°C to 0°C + Heat used to melt at 0°C + Heat used to reach 40°C from 0°C

To do this, we require the specific heat capacity of ice, latent heat of ice and the specific heat capacity of water. All will be obtained from literature.

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Heat gained by ice in taking the total temperature to 40°C = mCᵢ ΔT + mL + mC ΔT = m(2108)(0 - (-20)) + m(334000) + m(4186)(40 - 0) = 42160m + 334000m + 167440m = 543600 m

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543600 m = 36627.5

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