Ask question

Ask question

All categories

SCORPION-xisa [38]

2 years ago

13

Suppose the total momentum of two masses before a collision is 100 kg m/s. What is the total momentum of the two masses after th

ey collide? A. 0 kg m/s B. 50 kg m/s C. 100 kg m/s D. 200 kg m/s Is the answer D?

1 answer:

soldier1979 [14.2K]2 years ago

4 0

No, momentum is conserved so:
momentum before=momentum after
it is C. 100 kg m/s

You might be interested in

An object is at rest in front of a compressed spring. It travels over a surface that exerts a kinetic frictional force on it and

PolarNik [594]

Answer:

the object will travel 0.66 meters before to stop.

Explanation:

Using the energy conservation theorem:

$E_i+K_i+W_f=K_f+U_f$

The work done by the friction force is given by:

$W_f=F_f*d\\W_f=\µ*m*g*d\\W_f=0.35*4*9.81*d\\W_f=13.7d[J]$

so:

$\frac{1}{2}1800*(10*10^{-2})+0-13.7d=0+0\\d=0.66m$

3 0

3 years ago

Please correct answers only, if you don’t know, ignore. Please answer this or am I correct?

Wewaii [24]

Answer:

C is correct.

Explanation:

5 0

3 years ago

Read 2 more answers

Where is the 3rd quadrant

jeka94

The 3rd Quadrant is the lower left one on a graph,
where ' x ' and ' y ' are both negative.

Your picture is completely unrelated to this question.

4 0

3 years ago

Capacitor 2 has half the capacitance and twice the potential difference as capacitor 1. What is the ratio (U_{\rm C})_1/\,(U_{\r

IrinaK [193]

Answer:

1/2

Explanation:

The energy stored in a capacitor is given by

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V is the potential difference

Calling $C_1$ the capacitance of capacitor 1 and $V_1$ its potential difference, the energy stored in capacitor 1 is

$U=\frac{1}{2}C_1 V_1^2$

For capacitor 2, we have:

- The capacitance is half that of capacitor 1: $C_2 = \frac{C_1}{2}$

- The voltage is twice the voltage of capacitor 1: $V_2 = 2 V_1$

so the energy stored in capacitor 2 is

$U_2 = \frac{1}{2}C_2 V_2^2 = \frac{1}{2}\frac{C_1}{2}(2V_1)^2 = C_1 V_1^2$

So the ratio between the two energies is

$\frac{U_1}{U_2}=\frac{\frac{1}{2}C_1 V_1^2}{C_1 V_1^2}=\frac{1}{2}$

4 0

3 years ago

What is the final speed of a lion initially running at a speed of 30 m/s, if it accelerates at

cricket20 [7]

The final speed of a lion running 30 m/s accelerates at a rate of 3 m/s3 for 5 seconds it’s 3.2

8 0

2 years ago