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ELEN [110]
3 years ago
5

Why does an energy transfer not always result in phase change?

Physics
2 answers:
Alex Ar [27]3 years ago
6 0

Answer:

Explanation:

The energy transfer are not changing in kinetic energy. They are changes in bonding energy between the molecules.

mash [69]3 years ago
4 0

Answer:

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. "If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance

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What are the minimum requirements for airplane operations under special VFR in Class D airspace at night?
sdas [7]

Answer:

The minimum requirements for airplane operations under special VFR in Class D airspace at night are;

The pilot must be instrument rated, and

The airplane must be IFR equipped.

Pilots flying into Class D airspace must maintain at least three statute miles visibility.

In addition, pilots must remain at least 500 feet below clouds, 1,000 feet above clouds, and stay 2,000 feet away from horizontal clouds while in Class D airspace.

5 0
4 years ago
Which of of the following is a physical change ice melting into a puddle of water,Leaves changing color in fall, Or baking a cak
Tom [10]

Answer:

ice melting

Explanation:

Because once it melts you can change it back to ice.

4 0
4 years ago
A cube of ice at an initial temperature of -15.00°C weighing 12.5 g total is placed in 85.0 g of water at an initial temperature
Leona [35]

<u>Answer:</u> The specific heat of ice is 2.11 J/g°C

<u>Explanation:</u>

When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of ice = 12.5 g

m_2 = mass of water = 85.0 g

T_{final} = final temperature = 22.24°C

T_1 = initial temperature of ice = -15.00°C

T_2 = initial temperature of water = 25.00°C

c_1 = specific heat of ice = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

12.5\times c_1\times (22.24-(-15))=-[85.0\times 4.186\times (22.24-25)]

c_1=2.11J/g^oC

Hence, the specific heat of ice is 2.11 J/g°C

3 0
4 years ago
Number 2!!! pls help 11 pointsss
zepelin [54]

Answer:

b

Explanation:

3 0
3 years ago
Read 2 more answers
At what location in a circuit is the electrical potential energy the greatest
Eduardwww [97]

It's not the potential energy.  It's just the potential.

It's greatest at the positive terminal of the battery or power supply.


4 0
4 years ago
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