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rjkz [21]
3 years ago
15

Individual M has longer limbs and muscles than Individual N. Both individuals lift the same amount of weight from the ground to

their shoulders an equal number of times. If all repetitions were completed in synchrony, which statement about the amount of work completed by the individuals is true? At the end of the workout:
A. Individual M will have done less work because the object was moved a greater distance
B. both individuals will have done the same amount of work because force was applied for the same duration of time.
C. Individual M will have done more work because the muscle contracted faster to achieve synchrony with Individual N
D. Individual N would have done less work because the object was moved a shorter distance
Chemistry
1 answer:
Elena L [17]3 years ago
5 0

Answer:

D. Individual N would have done less work because the object was moved a shorter distance

Explanation:

When a body is moved a given distance (x) by a specific force (F), the work done on the body is equivalent to F*x. This shows that work is proportional to the applied force and the distance traveled by the body. Therefore, the higher the distance the higher the work done and the lower the distance the lower the work done. The work done by Individual N is lower due to the shorter limbs that correspond to shorter distance.

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What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

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