It would be known as a meth_(insert - ane, - ene, and -yne) hydrocarbon.
1 bond = -ane
2 bonds = - ene
And so on.
Answer:
The splash cause the volume of the block to be too high
Explanation:
This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.
Answer : The concentration of and at equilibrium is, 0.0158 M and 0.00302 M respectively.
Explanation :
First we have to calculate the concentration of
Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:
Initial conc. 0.0163 0.00415 0.00276
At eqm. (0.0163-2x) (0.00415+x) (0.00276+x)
As we are given:
Concentration of at equilibrium = 0.00467 M
That means,
(0.00415+x) = 0.00467
x = 0.00026 M
Concentration of at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M
Concentration of at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M