How many moles of SnF₂ will be produced along with 48 grams of H₂? *
1 answer:
Answer:
The correct option is;
24 moles
Explanation:
Here, we have the reaction as follows;
Sn(s) + 2HF(g) → SnF₂ (s) + H₂ (g)
Therefore, one mole of Sn reacts with 2 moles HF to form one mole of SnF₂ and one mole of H₂
Molar mass of H₂ = 2.01588 g/mol
Therefore, the number of moles of H₂ in 48 grams of H₂ is given by the relation;
Since one mole each of SnF₂ and H₂ are produced, the number of moles of SnF₂ produced = 24 moles.
The number of moles of SnF₂ that will be produced is 24 moles.
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Answer:
Ethyl propionate
Explanation:
Calculating the double bond equivalence as:
DBE = C - (H/2) - (X/2) + (N/2) +1
Where
C is the number of carbon atoms
N is the number of nitrogen atoms
X is the number of halogens
H is the number of hydrogen atoms
So, according to the formula,
DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1
It means there is one double bond or one ring.
from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.
From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.
The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have
.
Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.
So the compound is ethyl propionate
