Question

How many moles of SnF₂ will be produced along with 48 grams of H₂? *

Answer 1

Answer:

The correct option is;

24 moles

Explanation:

Here, we have the reaction as follows;

Sn(s) + 2HF(g) → SnF₂ (s) + H₂ (g)

Therefore, one mole of Sn reacts with 2 moles HF to form one mole of SnF₂ and one mole of H₂

Molar mass of H₂ = 2.01588 g/mol

Therefore, the number of moles of H₂ in 48 grams of H₂ is given by the relation;

$Number \ of \ moles \ of \, H_2 = \frac{Mass \ of H_2}{Molar \ Mass \ of H_2}=\frac{48}{2.01588} = 23.8109 \ moles \approx 24 \ moles$

Since one mole each of SnF₂ and H₂ are produced, the number of moles of SnF₂ produced = 24 moles.

The number of moles of SnF₂ that will be produced is 24 moles.