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Feliz [49]
3 years ago
10

ILL GIVE BRIANLIST

Chemistry
2 answers:
marshall27 [118]3 years ago
8 0

Answer:

increasing pressure

Explanation:

According to Henry's Law the amount of gas that can be dissolved in liquid water increase with the increase in pressure.

Henry’s law is given by the following equation,  

C = kP

where C is the concentration of the dissolved gas, k is a proportionality constant and P is the pressure of the gas.  

Thus the solubility of the gas is directly proportional to the pressure of the gas.

Nataly_w [17]3 years ago
4 0
Incresing Pressure will increases the amount of gas dissolved !!

so your answer is B !!

Extra : Cool example is Pepsi or coke !! CO2 is dissolved by high pressure
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Maurinko [17]

Answer:

partial pressure of gas D Pd = 15.5 kPa

Explanation:

As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.

P(Total) = P1+P2+P3.....

Given P(Total) = 35.7 kPa

Partial pressure of gas A Pa = 7.8 kPa

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There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)

Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa

Therefore, partial pressure of gas D Pd = 15.5 kPa

4 0
3 years ago
How many Helium atoms are in 12 grams of Helium?
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12gHe/1 × 1molHe/4.0026g × 6.02x10^23atomHe/1mol = 1.8 atoms
6 0
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What is difference between groups and periods? 8th grade science idk what to put it under
d1i1m1o1n [39]
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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

8 0
3 years ago
The enzyme urease catalyzes the breakdown of urea in the body. Urease breaks urea down to 2NH3+CO2. This is an example of a hydr
Alika [10]

Answer:

Look at the picture.

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8 0
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